FOIL and PEMDAS are both ways to solve mathematical equations.
<u>FOIL</u><u />
First
Outside
Inside
Last
<u>PEMDAS
</u>Parenthesis
Exponents
Multiplication &
Division
Addition &
S<u />ubtraction
FOIL is usually used to solve equations in two sets of parenthesis, for example:
(23+x)(5-4x)
PEMDAS is used to solve multiple-operation equations, such as:
5 x 4 + 6 - 2 x 7
Whew, hope this helped :D
Answer:

Step-by-step explanation:
A statement is given i.e. "ten to the eighth divided by ten to the negative third."
It means that 10 to power 8 divided by 10 to the power -3.
Mathematically,

We know that, 
Here, x = 10, a = 8 and b = -3
So,

So, the answer is 
Answer:

Step-by-step explanation:
Answer:
Step-by-step explanation:
Hello!
The variable of interest is
X: hourly wage of a high school student
X~N(μ;σ²)
X[bar]= $8.25
σ= $0.25
For a 95% CI for the average hourly wage for<u> 1 </u>high school student:
For this exercise you have to consider the sample size n=1
a) The margin of error of the CI is calculated as:
d=
* σ
1-α: 0.95 ⇒ α:0.05
1-α/2:0.975

d= 1.96 * 0.25= 0.49
b)
The formula for the interval is
X[bar] ±
* σ
[8.25 ± 0.49]
[7.76; 8.74]
With a 95% you'd expect the interval $[7.76; 8.74] to include the average hourly wage of one high school student in Illinois.
c)
Te calculated interval is $ [7.76; 8.74] the value $9.15 does nor fall within that acceptable range.
I hope this helps!