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Dmitry_Shevchenko [17]
2 years ago
15

HELP, I NEED IT ASAP!!!!!!!!!!!

Mathematics
2 answers:
Rom4ik [11]2 years ago
6 0

Answer:

it is 1,3 and 4

Step-by-step explanation:

solmaris [256]2 years ago
4 0

Answer:

its A C D

Step-by-step explanation:

did it on edg and got it right

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Completely factorize (2x+3)^-2 + 2x(2x+3)^-3
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Hello,

\dfrac{1}{(2x+3)^2} + \dfrac{2x}{(2x+3)^3} \\

= \dfrac{(2x+3)+2x}{(2x+3)^3}\\

= \dfrac{4x+3}{(2x+3)^3}
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2 years ago
If you pay $20 for 16 candy bars what is the cost for per candy
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3 years ago
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The measure of angle F is 130 degrees.
Vitek1552 [10]
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2 years ago
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Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete
icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

Fleet of 17 means that N = 17

4 are carrying nucleas weapons, which means that k = 4

9 are destroyed, which means that n = 9

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

P(X > 1) = 1 - P(X \leq 1)

In which

P(X \leq 1) = P(X = 0) + P(X = 1)

So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294

P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118

Then

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412

P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0
2 years ago
#5. What is the length of segment DC ?
DanielleElmas [232]

Answer:

6 units

Step-by-step explanation:

because since AC is 24 units long, and BC is half of AC, then that would be 12 units, and since DC is half of BC, then that would be six units.

6 0
3 years ago
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