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LekaFEV [45]
3 years ago
11

Given the graph of the function, determine the equation. (-4,3), (5, -6). Pls help

Mathematics
1 answer:
DedPeter [7]3 years ago
3 0
Your answer would be 4.3
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I believe this is pretty easy but it's: solve for x using common denominators 3/4(x+2)=x/(x+3) Answer choices below:
grigory [225]

Answer:

x = \frac{3}{4}

Step-by-step explanation:

Given

\frac{3}{4(x+2)} = \frac{x}{x+2}

multiply numerator/ denominator of \frac{x}{x+2} by 4, thus

\frac{3}{4(x+2)} = \frac{4x}{4(x+2)}

Since the denominators are common , equate the numerators, that is

4x = 3 ( divide both sides by 4 )

x = \frac{3}{4}

3 0
3 years ago
A local restaurant offers a deal if you purchase 3 medium pizzas you get to side dishes for free if you get a total of 8 side di
Anna71 [15]
The answer is 12 because every 3 pizzas you get 2 side dishes so 8 divided by 2 equals 4 and 4 times 3 is 12. Hope this helps
8 0
4 years ago
Read 2 more answers
Making high-stakes insurance decisions. The Journal of Economic Psychology (Sept. 2008) published the results of a high-stakes e
Andrej [43]

Answer:

a. P(24)=0.00007

b. P(23)=0.00018

c. There is significant difference between the probability of the rainy days and the probabilities of fire and theft.

The probability of theft would be overestimated by 76% and the probability of fire would be subestimated by 27%.

Step-by-step explanation:

The probabilities of two events ("fire"and "theft") are compared to the probabilities of a certain number of days of rain during July.

The probabilities of "fire"and "theft" are around P=0.0001, and we need to calculate if the probability of exactly 23 and exactly 24 days of rain July have approximately the same probability.

Rain frequencies for the months of July and August were shown to follow a Poisson distribution with a mean of 10 days per month.

The parameter then is:

\lambda=10

The probability of k days of rain is:

P(k)=\frac{10^ke^{-10}}{k!}

For 24 days, the probability is:

P(24)=\frac{10^{24}e^{-10}}{24!}=\frac{1*10^{24}*4.54*10^{-5}}{6.20*10^{23}}  = 0.00007

The probability of 23 days of rain is 27% less than P=0.0001.

For 23 days of rain, the probability is:

P(23)=\frac{10^{23}e^{-10}}{23!}=\frac{1*10^{23}*4.54*10^{-5}}{2.59*10^{23}}  = 0.00018

The probability of 23 days of rain is 76% more than P=0.0001.

There is significant difference between the probability of the rainy days and the probabilities of fire and theft.

The probability of theft would be overestimated by 76% and the probability of fire would be subestimated by 27%.

8 0
3 years ago
If 14 gallon of paint covers 112 of a wall, then how many quarts of paint are needed for the entire wall?
monitta

Answer:

8

Step-by-step explanation:

I used a calculator but i hope this helps

5 0
3 years ago
A sample of 100 people is classified by gender (male/female) and by whether they are registered voters. The sample consists of 8
uysha [10]

Answer:

12

Step-by-step explanation:

Given :

                                    Male         Female        Total

Registered                                                          60

Non registered                                                   40

Total                          20                  80    

Solution :

N= 100

Formula of expected frequency = E_{ij}=\frac{T_i \times T_j}{N}

E_{ij}= expected frequency for the ith row/jth columm.

T_i = total in the ith row

T_j= total in the jth column

N = table grand total.

So, using formula  E_{11}=\frac{T_1 \times T_1}{100}

E_{11}=\frac{60 \times 20}{100}

E_{11}=12

E_{12}=\frac{T_1 \times T_2}{100}

E_{12}=\frac{60 \times 80}{100}

E_{12}=48

E_{21}=\frac{T_2 \times T_1}{100}

E_{21}=\frac{40 \times 20}{100}

E_{21}=8

E_{22}=\frac{T_2 \times T_2}{100}

E_{22]=\frac{80 \times 40}{100}

E_{22}=32

Expected frequency table

                                    Male         Female        Total

Registered                  12                  48            60

Non registered           8                   32             40

Total                           20                  80    

So, the expected frequency for males who are registered voters are  E_{11}=12

5 0
3 years ago
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