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2 years ago

Geometry...Please help as soon as possible please and Thank you!!!

Mathematics

1 answer:

Kaylis [27]2 years ago

4 0

Answer:

I answered the question according to "ASA" Angle, side, angle

.....

Step-by-step explanation:

Note : I'm not a teacher but I'm quite sure about my answer...

Anyway...

If I'm wrong just tell me...

.....

GOOD LUCK... ❤️

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Help ASAP-----------------

lilavasa [31]

Answer:

Step-by-step explanation:

subtract 32 and 14

6 0

2 years ago

PLSSS HELPPP! I will give brainliest and 11 points!!

WARRIOR [948]

Answer:

4 units right and six units up

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2 years ago

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The length of a rectangle is 1 less than twice the width.

vladimir1956 [14]

$w-width\\2w-1-length\\w(2w-1)=2w^2-w-the\ area\\28\ ft^2-the\ area\\\\\text{The equation:}\\\\2w^2-w=28\qquad\text{subtract 28 from both sides}\\\\2w^2-w-28=0\\\\2w^2-8w+7w-28=0\\\\2w(w-4)+7(w-4)=0\\\\(w-4)(2w+7)=0\iff w-4=0\ \vee\ 2w+7=0\\\\w-4=0\qquad\text{add 4 to both sides}\\\boxed{w=4}\\\\2w+7=0\qquad\text{subtract 7 from both sides}\\2w=-7\qquad\text{divide both sides by 2}\\w=-3.5$

7 0

3 years ago

Read 2 more answers

Please help I learned this a while ago and forgot how to do it

lara [203]

Answer:

The slope-intercept form is $y=\frac{1}{2}x+\frac{11}{2}$

Step-by-step explanation:

To find the slope, use

$m=\frac{y^2-y^1}{x^2-x^1}$

Replace the x and y values with the points.

$m=\frac{7-5}{3-(-1)}$

Solve.

$m=\frac{2}{4}$

$m=\frac{1}{2}$

After that, find the y-intercept form.

Put the equation in point-slope form.

$y-5=\frac{1}{2}(x+1)$

Replace x with 0.

$y-5=\frac{1}{2}(0+1)$

$y-5=\frac{1}{2}$

Add 5 to both sides.

$y=5\frac{1}{2}$

Convert to improper fraction form.

The y-intercept is $\frac{11}{2}$

Now finally, write in slope-intercept form. (y=mx+b)

m is slope, b is the y-intercept.

7 0

2 years ago

A man steps out of a plane at a height of 4,000m above the ground falls 2,000m very quickly and then opens his parachute and slo

Mumz [18]

Answer:

Step-by-step explanation:

A man steps out of a plane at 4,000m of height above the ground.The point at which he jumps out of the plane would make a good reference point. However, if his acceleration is going to change as a result of him opening his parachute 2000m above the ground, a good reference point would be there. Keep in mind though, that his velocity at that instant would need to be known for it to be useful- otherwise the airplane reference point would be just as good with appropriate modeling....

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3 years ago