3 years ago

How do I find x and y for the problem below? -7x+2y=-13 1x-2y=11

Mathematics

1 answer:

d1i1m1o1n [39]3 years ago

7 0

For the first one :)))))))

You might be interested in

Giving brainly for correct answers

alukav5142 [94]

Answer:

Step-by-step explanation:

Integers are only positive and negative numbers:)

also 0

fractions are not integers

6 0

3 years ago

Read 2 more answers

Simplify the expression. Select the best answer from the choices below.<br> 2 - 8 + 3x + 8

skad [1K]

Answer:

3x + 2

Step-by-step explanation:

7 0

3 years ago

On your first draw, what is the probability of drawing a red card, without looking, from a shuffled deck containing 6 red cards,

Elis [28]

First divide 6/(6+6+8) =0.3
Then multiple it by 100 to get the probability percentage 30%

5 0

3 years ago

in circle F, points A,B,C,D, and E are located on the circle such that measure of C=119°, and BE is perpendicular AD. determine

VLD [36.1K]

Answer:

Measure of arc AE = 58°

Step-by-step explanation:

As shown: ABCD is a quadrilateral, ∠C = 119°

So, ∠C + ∠A = 180°

∴ ∠A = 180° - ∠C = 180° - 119° = 61°

ΔAGB is a right triangle at G

So, ∠A + ∠B = 90°

∴ ∠ABG = 90 - ∠A = 90 - 61 = 29°

Arc AE opposite to the angle ∠ABG

So, measure of arc AE = 2∠ABG = 2 * 29° = 58°

6 0

4 years ago

3.11 A shipment of 7 television sets contains 2 defective sets. A hotel makes a random purchase of 3 of the sets. If x is the nu

djverab [1.8K]

Answer:

Probability distribution for x:

$P(x=0)=0.3644\\\\P(x=1)=0.4373\\\\P(x=2)=0.1749\\\\P(x=3)=0.0233\\\\$

Step-by-step explanation:

We can model the number of defective sets in the group of TV sets (variable x) as a binomial variable, with sample size=3 and probability of success p=2/7≈0.2857.

The probability of k defective sets in the group is:

$P(x=k) = \dbinom{n}{k} p^{k}q^{n-k}$

So, we have this probabilty distribution for x:

$P(x=0) = \dbinom{3}{0} p^{0}q^{3}=1*1*0.3644=0.3644\\\\\\P(x=1) = \dbinom{3}{1} p^{1}q^{2}=3*0.2857*0.5102=0.4373\\\\\\P(x=2) = \dbinom{3}{2} p^{2}q^{1}=3*0.0816*0.7143=0.1749\\\\\\P(x=3) = \dbinom{3}{3} p^{3}q^{0}=1*0.0233*1=0.0233\\\\\\$

7 0

3 years ago