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kipiarov [429]
3 years ago
15

How do I find x and y for the problem below? -7x+2y=-13 1x-2y=11

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
7 0
For the first one :)))))))

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Help 7th grade math pls
madam [21]

Answer:

1,455 feet

Step-by-step explanation:

Step 1:

1 : 75    Ratio Inches to Feet

Step 2:

1 : 75 = 19.4 : x   Equation

Answer:

x = 1,455  Multiply

Hope This Helps :)

4 0
3 years ago
Read 2 more answers
PLEASE HELPPPPPPPPP!!!!?????
natta225 [31]

Answers:

  • Mean = 69
  • Median = 69
  • Mode = {68, 70}

===============================================

Explanations:

To get the mean, you add up all of the values and then you divide by N, where N is the number of values in the list. In this case, you'll divide by N = 8.

Adding up all the values gets you 70+68+70+72+68+66+65+73 = 552. Dividing that over 8 then leads to the arithmetic mean of 552/8 = 69

-------

To find the median, you'll first sort the values from smallest to largest. You should have this set {65, 66, 68, 68, 70, 70, 72, 73} after sorting. Next, cross off the smallest and largest values to end up with this smaller set {66, 68, 68, 70, 70, 72}. We do this so we can locate the middle-most item.

Repeat the process of crossing off the smallest and largest items to get {68, 68, 70, 70}. Do so one more time and we get {68,70}.

The midpoint of those two values is (68+70)/2 = 138/2 = 69. The median is 69. The mean and median may not always be the same value.

--------

The mode is the most frequent value. In this case, we have 68 and 70 show up exactly twice for each unique value. This is the most compared to the other unique values that only show up exactly once.

It is possible to have more than one mode, as long those values are more frequent than the rest. We denote the mode as a set, so the mode is {68, 70}

8 0
3 years ago
In the equation x + y = 8, find the value of x if y = 3<br><br> 3<br> 5<br> 7<br> 11
snow_lady [41]

Answer:

11

Step-by-step explanation:

x+y=8     y=3

x+3=8

-3     -3

x=11

7 0
3 years ago
Read 2 more answers
There were 18 students running in a race. How many different arrangements of first, second, and third place are possible?
swat32

Answer:

There are 18 choices for first place, 17 for second, and 16 for third.

Therefore, there are 18 x 17 x 16=4896

So there are 4,896 ways possible

Step-by-step explanation:

Hope this helps:)...if not then sorry for wasting your time and may God bless you:)

8 0
2 years ago
Which of the following are continuous?
goldenfox [79]
E and D are continuous
7 0
4 years ago
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