Well actually depending on the size, if a small one I would use liters, but if a large ones like Olympics I would use kilolitres.
<span>Find force,
9.8 m/s2 x 5.24 kg = </span><span>51.352 N </span>
Find work,
<span><span>51.352 N x 1.63 m= </span><span>83.70 N*m
</span>Example:
To solve this given word problem we can first identify the given and the apt formula to use in this phenomenon: Given: Force = 4, 500 N = 4, 500 kg-m/s^2 Acceleration = 5 m/s^2 </span>
<span>Formula: f=ma </span>
<span>Derivation: m = f/a </span>
<span>Solution: </span><span><span>
1. </span>M = f/a</span> <span><span>
2. </span>M = 4,500 kg-m/s^2 / 5 m/s^2</span> <span><span>
3. </span>M = 900 kg </span>
<span>Hence, the object’s mass is </span>900 kg.<span>
</span>
4(.75) + 3
3 + 3
6
-------------------
6(.50) - 2
3 - 2
1
P = 2 (l + w)
P = 2(6 + 1)
P = 2 x 7
P = 14
This is a function because each x value has its own y value.
The domain is all the x values : 1,2,3,4,5
The range is all the y values: 1,2,5,10,15
