Answer:
Given: ∆ABC with the altitudes from vertex B and C intersect at point M, so that BM = CM.
To prove:∆ABC is isosceles
Proof:-Let the altitudes from vertex B intersects AB at D and from C intersects AC at E( with reference to the figure)
Consider ΔBMC where BM=MC
Then ∠CBM=∠MCB......(1)(Angles opposite to equal sides of a triangle are equal)
Now Consider ΔDMB and ΔCME
∠D=∠E.......(each 90°)
BM=MC...............(given)
∠CME=∠BMD........(vertically opposite angles)
So by ASA congruency criteria
ΔDMB ≅ ΔCME
∴∠DBM=∠MCE........(2)(corresponding parts of a congruent triangle are equal)
Adding (1) and (2),we get
∠DBM+∠CBM=∠MCB+∠MCE
⇒∠DBC=∠BCE
⇒∠B=∠C⇒AB=AC(sides opposite to equal angles of a triangle are equal)⇒∆ABC is an isosceles triangle .
Answer:
h=-7
Step-by-step explanation:
-4(-6h - 7) = 9h + 10h - 7
24h+28=19h-7
Both side -28
24h+28-28=19h-7-29
24h=19h-35
Both side -19h
24h-19h=19h-19h-35
5h=-35
h=-7
Answer:
x-intercept: (-5,0)
y-intercept (0,25)
or in standard form 5x - y = -25
Step-by-step explanation:
Answer:3218680
cms
Step-by-step explanation: multiply 20x160934
Answer:
4
3
+
5
9
2
−
8
0
Step-by-step explanation: