Multiply r^2+7r+10/3 by 3r-30/r^2-5r-50
<span>=( r^2+7r+10)/3 (3r-30)/(r^2-5r-50) </span>
<span>=(r+2)(r+5)/3 3(r+10)/ (r-10)(r+5) </span>
<span>=3 (r+2)(r+5)(r+10)/3(r-10)(r+5) </span>
<span>=(r+2)(r+10)/(r-10)</span>
Answer:
5
Step-by-step explanation:
The integers 5 and 5 sum to 10 and have the largest possible product.
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The two numbers will be x and (10-x). Their product is x(10-x), which describes a downward-opening parabola with zeros at x=0 and x=10. The maximum (vertex) of that parabola is halfway between the zeros, at x=5. Both integers have the same value: 5. Their product is 25.
If there is a requirement the integers be distinct, then 6 and 4 are the integers of choice. Their product is 24.
Answer: x = {-1, -3, 2}
<u>Step-by-step explanation:</u>
x³ + 2x² - 5x - 6 = 0
Use the rational root theorem to find the possible roots: ±1, ±2, ±3, ±6
Use Long division, Synthetic division, or plug them into the equation to see which root(s) work <em>(result in a remainder of zero)</em>.
I will use Synthetic division. Let's try x = 1
1 | 1 2 -5 -6
|<u> ↓ 1 3 -2 </u>
1 3 -2 -8 ← remainder ≠ 0 so x = 1 is NOT a root
Let's try x = -1
- 1 | 1 2 -5 -6
|<u> ↓ -1 -1 6 </u>
1 1 -6 0 ← remainder = 0 so x = -1 is a root!
The coefficients of the reduced polynomial are: 1, 1, -6 --> x² + x - 6
Factor: x² + x - 6
(x + 3)(x - 2)
Set those factors equal to zero to solve for x:
x + 3 = 0 --> x = -3
x - 2 = 0 --> x = 2
Using Synthetic Division and Factoring the reduced polynomial, we found
x = -1, -3, and 2
Which set of ordered pairs represents a function? A {(22, 5), (23, 10), (22, 7), (23, 5)} B {(22, 5), (26, 10), (23, 7), (23, 5)
balu736 [363]
Answer:
C
Step-by-step explanation:
A function is a special kind of relation in which each valid input gives exactly one output.
C {(22, 10), (23, 10), (24, 7), (25, 5)}
So C is the correct option.
