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Gelneren [198K]
3 years ago
13

A rectangular swimming pool can hold 1,408 cubic feet of water. The pool is 22 feet long and has a depth of 4 feet. What is the

width of the pool?
Help!

Mathematics
1 answer:
Charra [1.4K]3 years ago
5 0

Answer: 16feet.

Step-by-step explanation:

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The diagram shows a circle inside a square.<br> a<br> 16 cm<br> Work out the area of the circle.
Aliun [14]

Answer:

Side of square=Diameter of circle=16

Radius= Diameter/2=16/2=8

Area of circle=4Πr²

=4*3.14*8²

=803.84cm²

3 0
3 years ago
Exercise 7.3.5 The following is a Markov (migration) matrix for three locations        1 5 1 5 2 5 2 5 2 5 1 5 2 5 2 5 2
fredd [130]

Answer:

Both get the same results that is,

\left[\begin{array}{ccc}140\\160\\200\end{array}\right]

Step-by-step explanation:

Given :

\bf M=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]

and initial population,

\bf P=\left[\begin{array}{ccc}130\\300\\70\end{array}\right]

a) - After two times, we will find in each position.

P_2=[P].[M]^2=[P].[M].[M]

M^2=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]\times \left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]

     =\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]

\therefore\;\;\;\;\;\;\;\;\;\;\;P_2=\left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right] \times\left[\begin{array}{ccc}130\\300\\70\end{array}\right] = \left[\begin{array}{ccc}140\\160\\200\end{array}\right]

b) - With in migration process, 500 people are numbered. There will be after a long time,

After\;inifinite\;period=[M]^n.[P]

Then,\;we\;get\;the\;same\;result\;if\;we\;measure [M]^n=\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]

                                   =\left[\begin{array}{ccc}140\\160\\200\end{array}\right]

4 0
2 years ago
PLSS HELP ASAP TYSM &lt;33 SORRY I COULDN'T FIND SCIENCE LOLL ​
dimaraw [331]

Answer:

Rock D.

Step-by-step explanation:

We can assume that the force that the catapult does is always the same.

So, here we need to remember Newton's second law:

F = m*a

force equals mass times acceleration.

Where acceleration is the rate of change of the velocity.

So, if we want the rock to hit closer to the catapult, the rock must be less accelerated than rock B.

So, we can rewrite:

a = F/m

So, as larger is the mass of the rock, smaller will be the acceleration of the rock after it leaves the catapult (because the mass is in the denominator). So if we want to have a smaller acceleration, we need to choose a rock with a larger mass than rock B.

Assuming that the mass depends on the size, the only one that has a mass larger than rock B is rock D.

So we can assume that rock D is the correct option.

5 0
3 years ago
Can someone answer it
Troyanec [42]
Answer what? This question? Oh, I'm answering it right now. Did you have another question out? Well, I can't see it. 
3 0
3 years ago
C+2c+12=75 find the value of c
tamaranim1 [39]

Answer:

c+2c+12=75

c = 21

Steps:

c+2c+12=75

Simplify both sides of the equation.

c+2c+12=75

(c+2c)+(12)=75(Combine Like Terms)

3c+12=75

3c+12=75

Subtract 12 from both sides.

3c+12−12=75−12

3c=63

Divide both sides by 3.

3 0
3 years ago
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