2 years ago

Please help i have no clue how to do this please solve and explain

Mathematics

1 answer:

Mariulka [41]2 years ago

6 0

The answer is c. 9z^7/y^6

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koda Buys 0.75 kg of cortos,which ia 5times the mas of the union he also Buys. How much does the union weigh?

kari74 [83]

Answer:

0.15kg

Step-by-step explanation:

Given data

We are told that

0.75 kg of cortos weights 5times the mas of the onion

We want to find the mass of 1 onion

Hence

0.75 kgcortos = 5 onions

x cortos = 1 onions

x= 0.75/5

x= 0.15kg

Hence 1 onion will weigh 0.15kg

4 0

2 years ago

How do you solve 3^(4x) = 3^(5-x)?

trasher [3.6K]

3^(4x) = 3^(5 - x)
4x = 5 - x
4x + x = 5
5x = 5
x = 5/5 = 1
x = 1

3 0

2 years ago

Someone help :d<br> look at the screenshot i inserted anything helps have a nice day :D

11111nata11111 [884]

Answer:

$18.24 (C)

Step-by-step explanation:

15.20 x 0.20 = 3.04

3.04 + 15.20 = 18.24

Hope this helped!

8 0

2 years ago

In a manufacturing process a random sample of 9 bolts manufactured has a mean length of 3 inches with a standard deviation of .3

Serggg [28]

Answer:

The correct option is (C) (2.769, 3.231).

Step-by-step explanation:

The confidence interval for mean when the standard deviation is not known is:

$CI=\bar x\pm t_{\alpha/2, (n-1)}\frac{s}{\sqrt{n}}$

Given:

$\bar x = 3\\s=0.3\\n=9\\\alpha =1-0.95=0.05$

Compute the critical value as follows:

$t_{\alpha/2, (n-1)}=t_{0.05/2, (9-1)}=t_{0.025, 8}=2.31$

**Use a <em>t</em>-table.

The 95% confidence interval for true mean length of the bolt is:

$CI=\bar x\pm t_{\alpha/2, (n-1)}\frac{s}{\sqrt{n}}\\=3\pm 2.31\times \frac{0.30}{\sqrt{9}}\\ =3\pm 0.231\\=(2.769, 3.231)$

Thus, the 95% confidence interval for true mean length of the bolt is (2.769, 3.231).

The correct option is (C).

7 0

2 years ago

Divide 7/9 by -11/7 then simplify

gayaneshka [121]

Invert the divisor and then multiply 7/9 by your result:

7 -7 -49
--- * ------ = ---------
9 11 99

6 0

2 years ago