From 9 P.M. to 5 A.M. the temperature dropped 20°, making the rate over 8 hours, -2.5° Per Hour. By 5 A.M., the temperature is -5° since we had to do 15 - 20. From 5 AM to 5 P.M. is 12 hours so -2.5 x 12 = -30 making 30 how much the temperature dropped between 5 A.M. to 5 P.M. Finally, our last equation is -5 - 30 making -35 our answer.
Answer:
The equation for the trend line would be y = -1/100x + 25
Step-by-step explanation:
In order to find the trend line, we first need to find the slope. To do so, we need to find two points on the line. The points we'll use are (0, 25) and (2500, 0). Next, we use the slope formula.
m(slope) = (y2 - y1)/(x2 - x1)
m = (0 - 25)/(2500 - 5)
m = -25/2500
m = -1/100
Now that we have this we can use the slope and the intercept in slope intercept form to model the trend line.
y = mx + b
y = -1/100x + 25
The answer is A y-28=3(x-6)
Answer:
I guess (c) is your answer. thanks!!
