Answer:
if I'm not wrong 41 is your answer
Answer:
A
Step-by-step explanation:
We know the y intercept is positive so that eliminates choice D.
y = 3x^2 -2x+1
This does not intercept the x axis
y = 3x^2 -6x+3
= 3(x^2 -2x+1)
3(x-1)^2
This intercepts the x axis at 1
This is not the equation for the graph
y = 3x^2 -7x+1
Let x = 1
y = 3-7+1
= -3
This will cross the x axis, so this cannot be the graph
<span>Simplifying
y(2x + 3y)(2x + 3y)
Multiply (2x + 3y) * (2x + 3y)
y(2x * (2x + 3y) + 3y * (2x + 3y))
y((2x * 2x + 3y * 2x) + 3y * (2x + 3y))
Reorder the terms:
y((6xy + 4x2) + 3y * (2x + 3y))
y((6xy + 4x2) + 3y * (2x + 3y))
y(6xy + 4x2 + (2x * 3y + 3y * 3y))
y(6xy + 4x2 + (6xy + 9y2))
Reorder the terms:
y(6xy + 6xy + 4x2 + 9y2)
Combine like terms: 6xy + 6xy = 12xy
y(12xy + 4x2 + 9y2)
(12xy * y + 4x2 * y + 9y2 * y)
(12xy2 + 4x2y + 9y3)</span>
People often draw hypothesis in research. Based on executing the test in Question 5, We reject the null hypothesis; the mean delivery time is different for every day of the week.
<h3>Why do we reject the null hypothesis?</h3>
Note that if the p-value of an experiment (Like the one above) is less than or found to be equal to the significance level of your test, one can reject the null hypothesis.
By that, we known that the data is in favors the alternative hypothesis. Hence the results gotten by you are statistically significant. If your p-value is found to be greater than your significance level, you then fail to reject the null hypothesis.
Learn more about hypothesis from
brainly.com/question/11555274
Question number 9
Angle 1 is 75. This is because If two parallel lines are cut by a transversal, the corresponding angles are congruent.
Angle 2 is 105. This is because If two parallel lines are cut by a transversal, the interior angles on the same side of the transversal are supplementary.
Question number 10
Angle 1 is 120. This is because If two parallel lines are cut by a transversal, the corresponding angles are congruent.
Angle 2 is 60. This is because If two parallel lines are cut by a transversal, the interior angles on the same side of the transversal are supplementary.
