Answer:
Claim 2
Step-by-step explanation:
The Inscribed Angle Theorem* tells you ...
... ∠RPQ = 1/2·∠ROQ
The multiplication property of equality tells you that multiplying both sides of this equation by 2 does not change the equality relationship.
... 2·∠RPQ = ∠ROQ
The symmetric property of equality says you can rearrange this to ...
... ∠ROQ = 2·∠RPQ . . . . the measure of ∠ROQ is twice the measure of ∠RPQ
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* You can prove the Inscribed Angle Theorem by drawing diameter POX and considering the relationship of angles XOQ and OPQ. The same consideration should be applied to angles XOR and OPR. In each case, you find the former is twice the latter, so the sum of angles XOR and XOQ will be twice the sum of angles OPR and OPQ. That is, angle ROQ is twice angle RPQ.
You can get to the required relationship by considering the sum of angles in a triangle and the sum of linear angles. As a shortcut, you can use the fact that an external angle is the sum of opposite internal angles of a triangle. Of course, triangles OPQ and OPR are both isosceles.
5.0 is your answer this is baby math what are you doing
Answer:
x = 2, y = 6
Step-by-step explanation:
Δ WXY is equilateral ( 3 congruent angles ), then the sides are equal
WY = WX , that is
y - 1 = 5 ( add 1 to both sides )
y = 6
Δ WYZ is isosceles ( 2 congruent base angles ) then the legs are congruent
YZ = WY , that is
x + 3 = 5 ( subtract 3 from both sides )
x = 2
Use this formula to help you find the answer V= LxWxH or V=BxH
Step-by-step explanation:
Sorry its messy but if you cant understand tell me
