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ad-work [718]
3 years ago
11

C. What is the difference between the percentage Kareem thinks he needs and the

Mathematics
1 answer:
olga2289 [7]3 years ago
6 0
168 maybe lol 727282 lol lol 83733
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A. Use composition to prove whether or not the functions are inverses of each other.
kogti [31]

A. In a composition of two functions the first function is evaluated, and then the second function is evaluated on the result of the first function. In other word, you are going to evaluate the second function in the first function.

Remember that you can evaluate function at any number just replacing the variable in the function with the number. For example, let's evaluate our function f(x) at x=1:

f(x)=\frac{1}{x-3}

f(1)=\frac{1}{1-3}

f(1)=\frac{1}{-2}

Similarly, to find the composition of f(x) andg(x), we are going to evaluate f(x) at g(x). In other words, we are going to replace x in f(x) with \frac{3x+1}{x}:

f(x)=\frac{1}{x-3}

f(g(x) = f(\frac{3x+1}{x} ) = \frac{1}{\frac{3x+1}{x} -3}

Remember that two functions are inverse if after simplifying their composition, we end up with just x. Let's simplify and see what happens.

f(g(x)=\frac{1}{\frac{3x+1}{x} -3}

f(g(x)=\frac{1}{\frac{3x+1-3x}{x} }

f(g(x)=\frac{1}{\frac{1}{x} }

f(g(x)=x

Now let's do the same for g(f(x)):

g(\frac{1}{x-3} )=\frac{3(\frac{1}{x-3})+1}{x}

g(\frac{1}{x-3} )=\frac{\frac{3}{x-3}+1}{x}

g(\frac{1}{x-3} )=\frac{\frac{3+x-3}{x-3}}{x}

g(\frac{1}{x-3} )=\frac{\frac{x}{x-3}}{x}

g(\frac{1}{x-3} )=\frac{x}{x(x-3)}

g(f(x))=\frac{x}{x(x-3)}

We can conclude that g(x) is the inverse function of f(x), but f(x) is not the inverse function of g(x).

B. The domain of a function is the set of all the possible values the independent variable can have. In other words, the domain are all the possible x-values of function.

Now, interval notation is a way to represent and interval using an ordered pair of numbers called the end points; we use brackets [ ] to indicate that the end points are included in the interval and parenthesis ( ) to indicate that they are excluded.

Notice that when x=0, g(x)=\frac{3(0)+1}{0} =\frac{0}{0}, so when x=0, g(x) is not defined; therefore we have to exclude zero from the domain of f(g(x)).

We can conclude that the domain of the composite function f(g(x)) in interval notation is (-∞,0)U(0,∞)

Now let's do the same for g(f(x)).

Notice that the composition is not defined when its denominator equals zero, so we are going to set its denominator equal to zero to find the values we should exclude from its domain:

x(x-3)=0

x=0 and x-3=0

x=0 and x=3

Know we know that we need to exclude x=0 and x=3 from the domain of g(f(x)).

We can conclude that the domain of the composition function g(f(x)) is (-∞,0)U(0,3)U(3,∞)

4 0
3 years ago
Read 2 more answers
Solve.
Feliz [49]

Answer:

D) x = -7.5

Step-by-step explanation:

x + 8 = 0.5

Subtract 8 from each side

x+8-8 = .5 -8

x = -7.5

6 0
3 years ago
Find the general solution of y\"+9y=t^2*e^3t+6.
Fofino [41]
We are given with the equation y"+ 9 y = t^2 * e^3 t + 6 and asked to determine the general solution to this equation. we convert the equation into r^2 + 9 = 0. The solution to this equation is r = +/- 3i. This solution converted to trigonometric function is equivalent to <span>y</span>= <span>C1 </span>cos3t + <span>C2 </span>sin<span>3t. </span>
3 0
3 years ago
Over the weekend, trigg and craig drove to lake of the pines to go fishing. now they're preparing to go home. trigg needs gas fo
Alecsey [184]
$1.35 x 10 = $13.50 for 10 gallons

$23.50 - $13.50 = $10.00

$1.35 x 7 = $9.45 for 7 more gallons

17 gallons is $22.45

17/27 = 459 miles but I'm missing the last bit of change so round it up to 460 for a total of miles

3 0
4 years ago
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A deceleration of 25 mph can be described by which absolute value statement? A) |-25| = 25 B) -|25| = 25 C) -|25| = -25 D) |-25|
insens350 [35]
The answer will be A. Hope it help!
4 0
3 years ago
Read 2 more answers
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