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2 years ago

10

On average, a student’s grade decreases 2 points for every 30 minutes they spend playing Fortnite. what is the y intercept , slo

pe, and equation?

1 answer:

aliina [53]2 years ago

6 0

Answer:

y intercept is 0,0 Slope is 15 equation is y=15x

You might be interested in

A) There are 100 students who play at least one of volleyball, soccer and hockey, of these 50 play au three games, 84 play socce

Scilla [17]

Answer:

<h2>i) 3</h2><h2>ii) 5</h2>

Step-by-step explanation:

Let H be the set of students who play Hokey

V be the set of students who play Volleyball

S be the set of students who play Soccer

======================================

card(volleyball only) = card(V) - [card(V∩H∩S) + card(V∩H only) + card(V∩S only)]

= 73 - [50 + (58-50) + (62-50)]

= 73 - [50 + 8 + 12]

= 73 - 70

= 3

………………………………………………

Card(Hokey only) = 100 - [3 + 8 + 50 + 10 + 12 + 12]

= 100 - 95

= 5

…………………

<u><em>Note</em></u> :

A Venn diagram might be helpful in such case.

5 0

1 year ago

Suiting at 6 a.m., cars, buses, and motorcycles arrive at a highway loll booth according to independent Poisson processes. Cars

dem82 [27]

Answer:

Step-by-step explanation:

From the information given:

the rate of the cars = $\dfrac{1}{5} \ car / min = 0.2 \ car /min$

the rate of the buses = $\dfrac{1}{10} \ bus / min = 0.1 \ bus /min$

the rate of motorcycle = $\dfrac{1}{30} \ motorcycle / min = 0.0333 \ motorcycle /min$

The probability of any event at a given time t can be expressed as:

$P(event \ (x) \ in \ time \ (t)\ min) = \dfrac{e^{-rate \times t}\times (rate \times t)^x}{x!}$

∴

(a)

$P(2 \ car \ in \ 20 \ min) = \dfrac{e^{-0.20\times 20}\times (0.2 \times 20)^2}{2!}$

$P(2 \ car \ in \ 20 \ min) =0.1465$

$P ( 1 \ motorcycle \ in \ 20 \ min) = \dfrac{e^{-0.0333\times 20}\times (0.0333 \times 20)^1}{1!}$

$P ( 1 \ motorcycle \ in \ 20 \ min) = 0.3422$

$P ( 0 \ buses \ in \ 20 \ min) = \dfrac{e^{-0.1\times 20}\times (0.1 \times 20)^0}{0!}$

$P ( 0 \ buses \ in \ 20 \ min) = 0.1353$

Thus;

P(exactly 2 cars, 1 motorcycle in 20 minutes) = 0.1465 × 0.3422 × 0.1353

P(exactly 2 cars, 1 motorcycle in 20 minutes) = 0.0068

(b)

the rate of the total vehicles = 0.2 + 0.1 + 0.0333 = 0.3333

the rate of vehicles with exact change = rate of total vehicles × P(exact change)

$= 0.3333 \times \dfrac{1}{4}$

= 0.0833

∴

$P(zero \ exact \ change \ in \ 10 minutes) = \dfrac{e^{-0.0833\times 10}\times (0.0833 \times 10)^0}{0!}$

P(zero exact change in 10 minutes) = 0.4347

c)

The probability of the 7th motorcycle after the arrival of the third motorcycle is:

$P( 4 \ motorcyles \ in \ 45 \ minutes) =\dfrac{e^{-0.0333\times 45}\times (0.0333 \times 45)^4}{4!}$

$P( 4 \ motorcyles \ in \ 45 \ minutes) =0.0469$

Thus; the probability of the 7th motorcycle after the arrival of the third one is = 0.0469

d)

P(at least one other vehicle arrives between 3rd and 4th car arrival)

= 1 - P(no other vehicle arrives between 3rd and 4th car arrival)

The 3rd car arrives at 15 minutes

The 4th car arrives at 20 minutes

The interval between the two = 5 minutes

<u>For Bus:</u>

P(no other vehicle other vehicle arrives within 5 minutes is)

= $\dfrac{6}{12} = 0.5$

<u>For motorcycle:</u>

$= \dfrac{2 }{12} = \dfrac{1 }{6}$

∴

The required probability = $1 - \Bigg ( \dfrac{e^{-0.5 \times 0.5^0}}{0!} \times \dfrac{e^{-1/6}\times (1/6)^0}{0!} \Bigg)$

= 1- 0.5134

= 0.4866

6 0

2 years ago

Lane's arm span is 61 inches. If his height is 1⁄4 foot longer than his arm span, how tall is he? feet and inches

melamori03 [73]

If lane's are span is 61 inches. his height is 1/4 foot long than his arm span. his height is <span>5 ft 3 inches </span>

6 0

2 years ago

5 1/4 ft; a= 12 ft 2

jonny [76]

1Answer:

Step-by-step explanation:

7 0

2 years ago

2. Express the number 1750 as a product of prime factors of the form:<br> p * qr * s

Artyom0805 [142]

9514 1404 393

Answer:

1750 = 2 · 5³ · 7

Step-by-step explanation:

It is often helpful to start with divisibility rules when finding prime factors of a small composite number.

The least-significant digit is even, so we know 2 is a factor.

1750/2 = 875

The least significant digit is 5, so we know 5 is a factor.

875/5 = 175

175/5 = 35

35/5 = 7

7 is a prime number, so we're done.

The factorization is ...

1750 = 2 · 5³ · 7

4 0

2 years ago