Ask question

Ask question

All categories

2 years ago

10

On average, a student’s grade decreases 2 points for every 30 minutes they spend playing Fortnite. what is the y intercept , slo

pe, and equation?

1 answer:

aliina [53]2 years ago

6 0

Answer:

y intercept is 0,0 Slope is 15 equation is y=15x

You might be interested in

Hey! I would really love it if someone could help me

Umnica [9.8K]

Alrigth and B....

I think??????????? If I get it wrong im sorry ;-;

4 0

2 years ago

What strategy would be the best to solve this problem?

neonofarm [45]

Answer:

32 years old

Step-by-step explanation:

Reverse what the teacher said. Half 120 to get 60. Subtract 28 from 60. The teacher is 32.

5 0

2 years ago

Please help me explain as well. I will give brainliest.

garik1379 [7]

Answer:

Step-by-step explanation:

6 0

2 years ago

A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f

Andrews [41]

Answer:

$A = \frac{P}{r}\left( e^{rt} -1 \right)$

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

$\frac{dA}{rA+P} = dt$

Integration on both sides gives

$\int \frac{dA}{rA+P} = \int dt$

where $c$ is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

$\int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c$

Therefore,

$\frac{1}{r} \ln |rA+P| = t+c$

Multiply both sides by $r.$

$\ln |rA+P| = rt+c_1, \quad c_1 := rc$

By taking exponents, we obtain

$e^{\ln |rA+P|} = e^{rt+c_1} \implies |rA+P| = e^{rt} \cdot e^{c_1} rA+P = Ce^{rt}, \quad C:= \pm e^{c_1}$

Isolate $A$ .

$rA+P = Ce^{rt} \implies rA = Ce^{rt} - P \implies A = \frac{C}{r}e^{rt} - \frac{P}{r}$

Since $A = 0$ when $t=0$ , we obtain an initial condition $A(0) = 0$ .

We can use it to find the numeric value of the constant $c$ .

Substituting $0$ for $A$ and $t$ in the equation gives

$0 = \frac{C}{r}e^{0} - \frac{P}{r} \implies \frac{P}{r} = \frac{C}{r} \implies C=P$

Therefore, the solution of the given differential equation is

$A = \frac{P}{r}e^{rt} - \frac{P}{r} = \frac{P}{r}\left( e^{rt} -1 \right)$

4 0

2 years ago

Solve for X when m<2 = 8x <br><br> (I don’t really understand how to solve this. Please help??)

lozanna [386]

Answer:

x = 1/4

Step-by-step explanation:

First u swap the sides of the equation

8x = 2

then you divide both sides by 8 which gets you 1/4 or 0.025

6 0

2 years ago