New perimeter is 4040-2424= 1616
original, let x and y be length and width
2x + 2y = 4040
new
2x/2 +2y/3 = 1616
x +2y/3 = 1616
x = 1616 - 2y/3
sub this x value into first eq
2(1616-2y/3) + 2y = 4040
3232 - 4y/3 + 2 = 4040
put like terms together
-4y/3+2y=4040-3232
2y/3=808
multiply both sides by 3
2y = 2424
divide both sides by 2
y=1212
sub this y value into any eq. i chose eq 1
2x+2(1212)= 4040
2x = 4040 - 2(1212)
2x = 1616
x = 808
so the length is 808 and the width is 1212
The answer I think is (c) 3
The area is 36 units squared.
You have three ways you can solve this question.
Method 1:
Split the rhombus into two equal triangles.
You will get triangle ACD and triangle ACB.
Count the base length and height length of each triangle using the diagram.
You will get base = 6 units and height = 6 units. Plug this into the area of a triangle and then multiply it by 2.
A = bh/2 * 2
A = 6(6) / 2 * 2
A = 36 / 2 * 2
A = 18 * 2
A = 36
Method 2:
Calculate the length of DP.
The length of line segment DP is √28.8
Calculate the length of DC.
The length of line segment DC is 3√5
Put into equation A = bh.
A = bh
A = 3√5(√28.8)
A = 36
Method 3:
Calculate the length of each diagonal and put into formula A = 1/2(d1 * d2)
Diagonal DB = 12 units
Diagonal AC = 6 units
A = 1/2(d1 * d2)
A = 1/2(12 * 6)
A = 1/2(72)
A = 36
I love procrastinating my history essay for this :D
Answer:
4(2k-1)
Step-by-step explanation:
