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alexandr1967 [171]
3 years ago
8

Simplify the expression. 8x + 7 – 3x

Mathematics
2 answers:
marshall27 [118]3 years ago
8 0
8x + 7 -3x=
15x - 3x=
12x

DIA [1.3K]3 years ago
6 0
5x+7
Hope this helps :)

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Item 14
dsp73

Answer:

13/21

Step-by-step explanation:

5 0
2 years ago
Which relation does not represent a function? A) a vertical line B) y = 5 9 x - 3 C) a horizontal line D) {(1, 7), (3,7), (5, 7)
Alisiya [41]

Answer:

A) a vertical line does not represent a function.

Step-by-step explanation:

For a relation to be a function for each value of x there must be only one value of y. In other words a function is one in which each value in the domain set corresponds to only one value in the range set.

Let us check for this condition in the give choices:

A) a vertical line

A vertical line is given as x=a which meas it is parallel to y-axis and has infinite number of y values for a single x value.

So, its Not a function

B) y=\frac{5}{9}x-3

For the given equation, on plugging in some x value will give a single y value.

So, its a Function

C) a horizontal line

A horizontal line is given as y=a which meas it is parallel to x-axis and has infinite number of x values giving a single y value.

So, its a Function

D) {(1, 7), (3,7), (5, 7), (7,7)}

For the given set for different x valuesthere is only one y value.

So, its a Function

4 0
3 years ago
Read 2 more answers
What is the value of (−23) –[(−25) – {(−17) –(−19)}
o-na [289]
The answer is four.
5 0
3 years ago
PLEASE HELP!!!!!!!!!!!!! DUE SOON
Sergio039 [100]

\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ h=-16t^2+\stackrel{\stackrel{v_o}{\downarrow }}{65}t


now, take a look at the picture below, so for 2) and 3) is the vertex of this quadratic equation, 2) is the y-coordinate and 3) the x-coordinate.


\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ h=\stackrel{\stackrel{a}{\downarrow }}{-16}t^2\stackrel{\stackrel{b}{\downarrow }}{+65}t\stackrel{\stackrel{c}{\downarrow }}{+0} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left( -\cfrac{65}{2(-16)}~~,~~0-\cfrac{65^2}{4(-16)} \right) \implies \left( \cfrac{65}{32}~,~0- \cfrac{4225}{-64}\right)


\bf \left( \cfrac{65}{32}~,~0+ \cfrac{4225}{64}\right)\implies \left( \stackrel{seconds}{2\frac{1}{32}}~~,~~ \stackrel{feet~hight}{66\frac{1}{64}}\right)

6 0
3 years ago
Drag a description to match each equation.
AnnZ [28]

Given:

The descriptions and equations. The equations are

y=4x

y=x+4

To find:

The correct description for each equation and match them.

Solution:

We know that, "+" is used for more and "×" is used for times.

Additive: y is 4 more than x.

y=x+4

Additive: x is 4 more than y.

x=y+4

Multiplicative: y is 4 times x.

y=4x

Multiplicative: x is 4 times y

x=4y

Therefore, the correct description for the equation y=4x is "Multiplicative: y is 4 times x " and the correct description for the equation y=x+4 is "Additive: y is 4 more than x. "

4 0
3 years ago
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