How many whole numbers are less than n+1

Mathematics

1 answer:

andreev551 [17]3 years ago

6 0

Answer:

$n$ .

Step-by-step explanation:

Assuming that $n \in Z^{+}$ , then all number less than $n+1$ are

$n+1-1=n$

Notice that the "plus one" indicates that the whole number shown by the expression $n+1$ indicates a whole number greater than $n\\$ by one unit. So, we just subtract one whole unit to achive a number less than the given expression.

Therefore, the answer is $n$ .

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7 0

2 years ago

The set of ordered pairs represents a

Murrr4er [49]

Answer:

The rule that represents the function is $y=x^2+1$ therefore the function is $f(x)=x^2+1$

Step-by-step explanation:

We have 5 ordered pairs in the plane xy. This means that every pair has the form (x, y).

Then, we have 5 values of x, which will give us 5 values of y, using the rule that represents the function.

The easy evaluation is that when x=0, the value of y is y=1, and then we can evaluate the rule for x=-1, and x=1, the value of y is the same, y=2. We can see here that we have a parabolic function, that is not centered in the origin of coordinates because when x=0, y=1.

So we propose the rule $y=x^2+1$ which is correct for the first 3 values of x.

Now, we evaluate the proposed rule when x=2, and when x=3. This evaluations can be written as

$f(2)=2^2+1=5$