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lorasvet [3.4K]
3 years ago
13

How many whole numbers are less than n+1

Mathematics
1 answer:
andreev551 [17]3 years ago
6 0

Answer:

n.

Step-by-step explanation:

Assuming that n \in Z^{+}, then all number less than n+1 are

n+1-1=n

Notice that the "plus one" indicates that the whole number shown by the expression n+1 indicates a whole number greater than n\\ by one unit. So, we just subtract one whole unit to achive a number less than the given expression.

Therefore, the answer is n.

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Find Ms. Buggie's mistake in the following problem. Then, give what the correct answer should be.
sdas [7]

Answer:

Mrs. Buggie should have Subtracted 13 instead of adding 13

LKA = 94°

Step-by-step explanation:

Lets work backwards from the equation so far:

40 = x+ 13

x + 13 = 40

We should subtract 13 because we are adding a number and 13 to 40

Imagine this:

You have 5 apples, but you bought some more and now you have 10

equation would be:

5+x = 10

subtract 5 from 10 to get 5

So you bought 5 apples

Back to the Question:

40 - 13 = 27

3(27) + 13 = 81+13 = 94°

Answer = 94°

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

8 0
3 years ago
Exact decimals of 7 5/6​
iris [78.8K]

Answer:

7.83 repeating

Step-by-step explanation:

Cal’s

3 0
3 years ago
Read 2 more answers
Which point is not on the graph of the equation y=10+x
RSB [31]

Answer:

C. (8, 2)

Step-by-step explanation:

To find which point is not on the graph, find which set of coordinates makes the equation incorrect.

When plugged into the equation, the point (8, 2) makes it incorrect:

y = 10 + x

2 = 10 + 8

2 = 18

2 \neq 18

The equation is incorrect because 2 is not equal to 18.

So, the point that is not on the graph is C. (8, 2)

6 0
2 years ago
If 1 pint is equal to 2 cups, then 5 pints would equal how many cups
zmey [24]

If 1 pint is equal to 2 cups then 5 pints equals 10 cups

5 times 2 equals 10.

4 0
2 years ago
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What are the restrictions of the domain of the function F(x) = 1/x^2-9
Sonbull [250]
f(x)=\frac{1}{x^2-9}

The denominator can't be equal to 0.
x^2-9 \not= 0 \\
x^2 \not= 9 \\
x \not= -3 \ \land \ x \not= 3

The domain is all numbers except -3 and 3.
x \in \mathbb{R} - \{-3, 3 \}
6 0
3 years ago
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