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alukav5142 [94]
3 years ago
12

Multiply mixed numbers 5 times 1 3/4=

Mathematics
2 answers:
Llana [10]3 years ago
7 0

Answer:

8 3/4

Step-by-step explanation:

insens350 [35]3 years ago
3 0

Answer: 8.75 is your answer

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Need help asap please​
victus00 [196]

Answer:

z=3.3 repeating

Step-by-step explanation:

Move all terms that don't contain  z  to the right side and solve.

7 0
3 years ago
9/20
NISA [10]

For this case we must find the solution of the following quadratic equation:

x ^ 2 + 5x + 7 = 0

Where:

a = 1\\b = 5\\c = 7

Then, the solution is given by:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

Substituting the values:

x = \frac {-5 \pm \sqrt {5 ^ 2-4 (1) (7)}} {2 (1)}\\x = \frac {-5 \pm \sqrt {25-28}} {2}\\x = \frac {-5 \pm \sqrt {-3}} {2}

By definition we have:i ^ 2 = -1

x = \frac {-5 \pm \sqrt {3i ^ 2}} {2}\\x = \frac {-5 \pm i \sqrt {3}} {2}

Thus, we have two complex roots.

Answer:

The equation has no real roots.

4 0
4 years ago
What is the rule for the pattern 3 12 6 24 12 48 24
schepotkina [342]

Multiply by 4 is your rule

3 x 4 = 12

6 x 4 = 24

12 x 4 = 48

To solve for the answer for 24, multiply it by 4

24 x 4 = 96

96 is the match for 24

hope this helps

8 0
3 years ago
Read 2 more answers
HELP! Find the value of sin 0 if tan 0 = 4; 180 < 0< 270
BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

\large \boxed{sin \theta = tan \theta cos \theta} \\  \large \boxed{tan^{2}  \theta + 1 =  {sec}^{2} \theta}

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

\large{ {4}^{2}  + 1 =  {sec}^{2} \theta } \\  \large{16 + 1 =  {sec}^{2} \theta } \\  \large{ {sec}^{2}  \theta = 17}

As we know, sec²θ = 1/cos²θ.

\large \boxed{sec \theta =   \frac{1}{cos \theta} } \\  \large \boxed{ {sec}^{2}  \theta =  \frac{1}{ {cos}^{2}  \theta} }

And thus,

\large{  {cos}^{2}  \theta =  \frac{1}{17}}   \\ \large{cos \theta =  \frac{ \sqrt{1} }{ \sqrt{17} } } \\  \large{cos \theta =  \frac{1}{ \sqrt{17} }  \longrightarrow  \frac{ \sqrt{17} }{17} }

Since the given domain is 180° < θ < 360°. Thus, the cosθ < 0.

\large{cos \theta =   \cancel\frac{ \sqrt{17} }{17} \longrightarrow cos \theta =  -  \frac{ \sqrt{17} }{17}}

Then use the Identity of sinθ = tanθcosθ to find the sinθ.

\large{sin \theta = 4 \times ( -  \frac{ \sqrt{17} }{17}) } \\  \large{sin \theta =  -  \frac{4 \sqrt{17} }{17} }

Answer

  • sinθ = -4sqrt(17)/17 or A choice.
4 0
3 years ago
Karim says the ratio of the distance he ran to the distance Shawn ran 4:3 give three possibilities for the distance each could h
jok3333 [9.3K]
Karim=4,8km,12km,16km Shawn=3,6km,9km,12km
4 0
4 years ago
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