The height of the kite above the ground is 58.68 ft
Let x be the height of the kite above Chee's hand.
The height of the kite above Chee's hand, the string and the horizontal distance between Chee and the kite form a right angled triangle with hypotenuse side, the length of the string and opposite side the height of the kite above Chee's hand.
Since we have the angle of elevation from her hand to the kite is 29°, and the length of the string is 100 ft.
From trigonometric ratios, we have
tan29° = x/100
So, x = 100tan29°
x = 100 × 0.5543
x = 55.43 ft.
Since Chee's hand is y = 3.25 ft above the ground, the height of the kite above the ground, L = x + y
= 55.43 ft + 3.25 ft
= 58.68 ft to the nearest hundredth of a foot
So, the height of the kite above the ground is 58.68 ft
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brainly.com/question/14350740
Annual interest - 4%
interest in 1 year
(4/100) * 4000
160
interest in 10 years
160 * 10
1600
So the amount you have at the end of 10 years
4000 + 1600
$ 5600
Answer:
A
Step-by-step explanation:
u move the decimal place left 2 spaces and u would get 0.024
The degree is "4" and the number of terms is "1"
