The total units of stationery he has would be 55 approximately.
<h3>What is a system of equations?</h3>
A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.
David keeps a range of stationery in his study.
Let the pencil is represented by x.
Let the erasers be represented by y.
Let the pens be represented by z.
Let n be the stationery.
5/7 of his stationery consists of pencils.
x = 5/7 n
1/6 of the remaining stationery consists of erasers.
y = 1/6 n
There are 20 pens in his study.
z = 20
The total stationery
X + y + z
5/7 n + 1/6 n + 20 = n
20 = n -23/ 36 n
20 = 13 / 36 n
n = 55.38
Therefore, the total units of stationery he has would be 55 approximately.
Learn more about equations here;
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Answer: 
Step-by-step explanation:
Given
Elisa run a total of
miles on Saturday and Sunday.
If she runs
miles on Saturday
Then, distance traveled on Sunday is given by
Answer:
(11) 7 thousandths (12) 7 ones (13) 7 tenths
Step-by-step explanation:
I got the answer because ummm thats where i saw the sevens were hehe
Answer:
stationary time is 2 hours 30 minutes
Traveling time is 3 hours 30 minutes
Step-by-step explanation:
There are two distinct line types on the graph
the horizontal ones and the ones going towards the upper part
The horizontal ones represent the stationary positions while the climbing one represent the traveling time
The horizontal ones are;
3 to 3:30
4-5
6:30 to 7:30
Time here is ;
30
minutes + 1 hour + 1 hour = 2 hours 30 minutes
The traveling time;
2 - 3
3:30 to 4
5 to 6:30
7:30 to 8
1 + 30 min + 1hr 30 + 30
= 3 hours 30 minutes
While Gary is using an indirect method to prove that segment DE is not parallel to segment BC in the triangle ABC shown ( I attached below the picture that should have support your question). And If he starts with the assumption that segment DE is parallel to segment BC I am pretty sure that <span>inequality which he will use to contradict the assumption is the first option : </span><span>
4:10 ≠ 6:14</span>