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kenny6666 [7]
2 years ago
10

I will give brainliest

Mathematics
1 answer:
alex41 [277]2 years ago
3 0

Answer:

x = 1.25

y = 1.75

Step-by-step explanation:

Since, the line that is 8 units long is parallel to the line that is ten units long.

Therefore, both the triangles are similar by AA postulate.

Corresponding sides of of the similar triangles are in proportion.

Therefore,

\frac{5}{x + 5}  =  \frac{7}{y + 7}  =  \frac{8}{10}  \\  \\  \implies \frac{5}{x + 5}  =  \frac{8}{10}  \\  \\ 5 \times 10 = 8(x + 5) \\  \\ 50 = 8x + 40 \\  \\ 50 - 40 = 8x \\  \\ 10 = 8x \\  \\  \frac{10}{8}  = x \\  \\ x = 1.25 \\  \\  \\ \frac{7}{y + 7}  =  \frac{8}{10} \\  \\ 7 \times 10 = 8(y + 7) \\  \\ 70 = 8y + 56 \\  \\ 70 - 56 = 8y \\  \\ 14 = 8y \\  \\  \frac{14}{8}  = y \\  \\ y = 1.75

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Step-by-step explanation:

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For all nonzero real numbers a,b,c, and d such that c/d = 3a/2b , which of the following expressions is equivalent to b?
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Step-by-step explanation:

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6 0
3 years ago
Help me? idk the answer :P
Alexus [3.1K]
\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{  n}}}\implies \cfrac{1}{a^{-{{  n}}}}\\\\
-------------------------------\\\\
\left( 2^8\cdot 3^{-5}\cdot 6^0 \right)^{-2}\left( \cfrac{3^{-2}}{2^3} \right)^4\cdot 2^{28}\impliedby \textit{let's do the first group}
\\\\
-------------------------------\\\\


\bf \left( 2^8\cdot \cfrac{1}{3^5}\cdot 1 \right)^{-2}\implies \left( \cfrac{2^8}{3^5} \right)^{-2}\implies \left( \cfrac{3^5}{2^8} \right)^{2}\implies \cfrac{3^{2\cdot 5}}{2^{2\cdot 8}}\implies \boxed{\cfrac{3^{10}}{2^{16}}}\\\\
-------------------------------\\\\
\textit{now the second group}\qquad \left( \cfrac{3^{-2}}{2^3} \right)^4\implies \left( \cfrac{\frac{1}{3^2}}{2^3} \right)^4\implies \left( \cfrac{1}{2^3\cdot 3^2} \right)^4

\bf \cfrac{1^4}{2^{4\cdot 3}\cdot 3^{4\cdot 2}}\implies \boxed{\cfrac{1}{2^{12}\cdot 3^8}}\\\\
-------------------------------\\\\
\textit{so we end up with\qquad }\cfrac{3^{10}}{2^{16}}\cdot \cfrac{1}{2^{12}\cdot 3^8}\cdot 2^{28}\implies \cfrac{3^{10}\cdot 2^{28}}{2^{16}\cdot 2^{12}\cdot 3^8}
\\\\\\
\cfrac{3^{10}\cdot 2^{28}}{2^{16+12}\cdot 3^8}\implies \cfrac{3^{10}\cdot 2^{28}}{2^{28}\cdot 3^8}\implies 3^{10}\cdot 2^{28}\cdot 2^{-28}\cdot 3^{-8}

\bf 3^{10-8}\cdot 2^{28-28}\implies 3^2\cdot 1\implies 3^2\implies 9
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2 years ago
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Setler79 [48]
You just do 40 times 0.825 and you will get your answer. 
4 0
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