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KIM [24]
3 years ago
14

The school is 100 meters from Miguel's house.

Mathematics
1 answer:
gregori [183]3 years ago
7 0

Answer:

i don't knoe if we can do it without the graph

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PLEASE HELP
miss Akunina [59]

In the smallest of the three triangles (with sides a,b,3) we have

a^2+3^2=b^2

In the second-largest triangle (with sides a,108), the length of the missing side is \sqrt{a^2+108^2}. Then in the largest triangle (with sides b,111,\sqrt{a^2+108^2}), we have

b^2+\left(\sqrt{a^2+108^2}\right)^2=(108+3)^2=111^2

\implies b^2+a^2+108^2=111^2

\implies b^2+a^2=657

Equivalently, we have

(a^2+9)+a^2=657\implies 2a^2=648\implies a^2=324\implies a=18

In turn, we find

b^2=18^2+3^2=298\implies b=\sqrt{333}=3\sqrt{37}

6 0
3 years ago
\dfrac k{2}+\dfrac12=3 <br> 2<br> k<br> ​ <br> + <br> 2<br> 1<br> ​ <br> =3
konstantin123 [22]

it's so hard to find it

Step-by-step explanation:

I didn't know

3 0
3 years ago
Read 2 more answers
How can I change Celsius to Fahrenheit
Ket [755]

You can use the formula,

 F = 9C/5 + 32


3 0
3 years ago
Read 2 more answers
HELP PLEASE! Can you please explain so I can understand how it was completed?
nlexa [21]

Answer:

(3 square root of 2 , 135°), (-3 square root of 2 , 315°)

Step-by-step explanation:

Hello!

We need to determine two pairs of polar coordinates for the point (3, -3) with 0°≤ θ < 360°.

We know that the polar coordinate system is a two-dimensional coordinate. The two dimensions are:

  • The radial coordinate which is often denoted by r.
  • The angular coordinate by θ.

So we need to find r and θ. So we know that:

r=\sqrt{x^{2}+y^{2}}       (1)

x = rcos(θ)                                   (2)

x = rsin(θ)                                    (3)

From the statement we know that (x, y) = (3, -3).

Using the equation (1) we find that:

r=\sqrt{x^{2}+y^{2}}=\sqrt{3^{2}+(-3)^{2}} = 3\sqrt{2}

Using the equations (2) and (3) we find that:

3 = rcos(θ)

-3 = rsin(θ)

Solving the system of equations:

θ= -45

Then:

r = 3\sqrt{2}[/tex]

θ= -45 or 315

Notice that  there are two feasible angles, they both have a tangent of -1. The X will take the positive value, and Y the negative one.

So, the solution is:

(3 square root of 2 , 135°), (-3 square root of 2 , 315°)

4 0
3 years ago
Please answer the question from the attachment.
xenn [34]
Change it into improper fraction to make it easier or just solve it as is.
=3\frac{5}{8}-2\frac{7}{8}
=\frac{29}{8}-\frac{23}{8}
=\frac{6}{8}=\frac{3}{4}            
OR
=3 \frac{5}{8}-2 \frac{7}{8}
divide it to two parts:
3-2=1 and \frac{5}{8}-\frac{7}{8}=\frac{-2}{8}
1\frac{-2}{8}⇒(1×8-2=6)
=\frac{6}{8}=\frac{3}{4}
6 0
3 years ago
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