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Law Incorporation [45]
3 years ago
11

Jenny scored a 23/28 on her math test. Tess scored a 81 percent. Who

Mathematics
2 answers:
ivanzaharov [21]3 years ago
6 0

Answer:

tess

Step-by-step explanation:

Aleks04 [339]3 years ago
6 0

Answer:

Jenny scored higher.

Step-by-step explanation:

You can figure out easy percentages by dividing the smaller number by the larger number, this will give you the said percent.

Jenny scored a 82% on her test while Tess scored an 81%

Hope this helps!

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Custom Office makes a line of executive desks. It is estimated that the total cost for making x units of their Senior Executive
Ivan

Answer:

(a) The average cost function is \bar{C}(x)=95+\frac{230000}{x}

(b) The marginal average cost function is \bar{C}'(x)=-\frac{230000}{x^2}

(c) The average cost approaches to 95 if the production level is very high.

Step-by-step explanation:

(a) Suppose C(x) is a total cost function. Then the average cost function, denoted by \bar{C}(x), is

\frac{C(x)}{x}

We know that the total cost for making x units of their Senior Executive model is given by the function

C(x) = 95x + 230000

The average cost function is

\bar{C}(x)=\frac{C(x)}{x}=\frac{95x + 230000}{x} \\\bar{C}(x)=95+\frac{230000}{x}

(b) The derivative \bar{C}'(x) of the average cost function, called the marginal average cost function, measures the rate of change of the average cost function with respect to the number of units produced.

The marginal average cost function is

\bar{C}'(x)=\frac{d}{dx}\left(95+\frac{230000}{x}\right)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g\\\\\frac{d}{dx}\left(95\right)+\frac{d}{dx}\left(\frac{230000}{x}\right)\\\\\bar{C}'(x)=-\frac{230000}{x^2}

(c) The average cost approaches to 95 if the production level is very high.

\lim_{x \to \infty} (\bar{C}(x))=\lim_{x \to \infty} (95+\frac{230000}{x})\\\\\lim _{x\to a}\left[f\left(x\right)\pm g\left(x\right)\right]=\lim _{x\to a}f\left(x\right)\pm \lim _{x\to a}g\left(x\right)\\\\=\lim _{x\to \infty \:}\left(95\right)+\lim _{x\to \infty \:}\left(\frac{230000}{x}\right)\\\\\lim _{x\to a}c=c\\\lim _{x\to \infty \:}\left(95\right)=95\\\\\mathrm{Apply\:Infinity\:Property:}\:\lim _{x\to \infty }\left(\frac{c}{x^a}\right)=0\\\lim_{x \to \infty} (\frac{230000}{x} )=0

\lim_{x \to \infty} (\bar{C}(x))=\lim_{x \to \infty} (95+\frac{230000}{x})= 95

6 0
3 years ago
A 40-foot ladder is leaning against a building and forms a 29.32° angle with the ground. how far away from the building is the b
zaharov [31]

The distance between the building and the ladder is 34.876 foot.

<h3>What is a Right Triangle?</h3>

A triangle in which one of the angle measure is equal to 90 degree is called a right triangle.

The ladder forms a right triangle with the building and the ground,

The length of the triangle is 40 foot

The angle made by the ladder is 29.32 degree

By using Trigonometric Ratios

cos 29.32 = Base /  Hypotenuse

cos 29.32 = Base / 40

0.8718 × 40 = Base

Base = 34.876 foot

Base is the distance between the building and the ladder.

Base of the ladder = 34.876 foot

To learn more about trigonometric functions from the given link

brainly.com/question/24336684

#SPJ4

8 0
2 years ago
Help with these two figured and you shall be granted points. Good deal, half off.
STALIN [3.7K]

Answer:

5. C - 180ft²

6. D - 120m³

Step-by-step explanation:

5.

(6.5 x 11) = 71.5

(6 x 2.5) = 15

(6 x 11) = 66

(2.5 x 11) = 27.5

6.

((7.5 x 4)/2)(8) = 120

7 0
3 years ago
Determine the domain of the function.
pav-90 [236]
Domain \ of \ \frac{\sqrt{x + 3}}{(x + 8)(x - 2)}=(-3\leq x < 2) \cup (2 < x < \infty)

i.e. x ≥ –3, x ≠ 2
4 0
3 years ago
Find the value of x if a,b, and c are collinear points an b is between a and c
MakcuM [25]
\sf Hello!

• \sf AB = x + 6
• \sf BC = 3x - 5
• \sf AC = 36 - x

\sf We're \:given\: that \:A,\: B\: and \:C \:are \:Collinear\: points

\sf Then,

\sf AB + BC = AC

⇒ \sf x + 6 + 3x - 5 = 36 - x

⇒ \sf x + 3x + 6 - 5 = 36 - x

⇒ \sf 4x + 1 = 36 - x

⇒ \sf 4x + x = 36 - 1

⇒ \sf 5x = 35

⇒ \sf x = \dfrac{\sf 35}{\sf 5}

⇒ \boxed{\sf x = 7}

\sf Hence,

\sf The\: value\: of\: x\: is\: D.\: 7

~ \sf iCarl
3 0
3 years ago
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