Answer:
10
Step-by-step explanation:
2 [32 - (4 - 1)³]
2[32 - (3)³]
2[32 - 27]
2[5]
10
No because the scale factors are different. You can see that QR compared to VT the scale factor is 2, but in RS and TU it's different, so they are not similar.
H(t) = -16t² + 60t + 95
g(t) = 20 + 38.7t
h(1) = -16(1²) + 60(1) + 95 = -16 + 60 + 95 = -16 + 155 = 139
h(2) = -16(2²) + 60(2) + 95 = -16(4) + 120 + 95 = -64 + 215 = 151
h(3) = -16(3²) + 60(3) + 95 = -16(9) + 180 + 95 = -144 + 275 = 131
h(4) = -16(4²) + 60(4) + 95 = -16(16) + 240 + 95 = -256 + 335 = 79
g(1) = 20 + 38.7(1) = 20 + 38.7 = 58.7
g(2) = 20 + 38.7(2) = 20 + 77.4 = 97.4
g(3) = 20 + 38.7(3) = 20 + 116.1 = 136.1
g(4) = 20 + 38.7(4) = 20 + 154.8 = 174.8
Between 2 and 3 seconds.
The range of the 1st object is 151 to 131.
The range of the 2nd object is 97.4 to 136.1
h(t) = g(t) ⇒ 131 = 131
It means that the point where the 2 objects are equal is the point where the 1st object is falling down while the 2nd object is still going up.
To solve this you will be needing to use PEMDAS!
Parenthesis exponents multiply divide add subtract!
So first parenthesis...
609-78=531
So now we write the problem like this
10*80+531-10^2
Now exponents
10^2 is a exponent so that =10*10 which = 100
So we write it out again like this: 10*80+531-100
Now we need to multiply from left to write
So 10*80=800
Re-write it:
800+531-100
So now we need to add from left to write
800+531=1331
1331-100=1231
So your answer is 1231.
Does this help any?
