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4 years ago

-3/4x+5/6y=15x-intercept=y-intercept=

Mathematics

1 answer:

Trava [24]4 years ago

5 0

To make this easier, you need to change the fractions by multiplication.

-3/4x=15 - First, you multiply 4 to both sides of the equation

(4)-3/4x=15(4)

-12/4x=60 - Simplify

-3x=60 - Divide by -3 on both sides

x=-20 -> (-20,0)

Do the same to find the y-intercept, to get (0,18)

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Help me, please?????

Paladinen [302]

Answer: The equation is true

Step-by-step explanation:

Since x=3 and y= 5

Substitute the values for x and y

y=2x-1

5=2(3)-1

5=6-1

5=5

⇒The equation is true

3 0

1 year ago

A field goal kicker lines up to kick a 44 yard (40m) field goal. He kicks it with an initial velocity of 22m/s at an angle of 55

Goryan [66]

Answer:

The ball makes the field goal.

The magnitude of the velocity of the ball is approximately 18.166 meters per second.

The direction of motion is -45.999º or 314.001º.

Step-by-step explanation:

According to the statement of the problem, we notice that ball experiments a parabolic motion, which is a combination of horizontal motion at constant velocity and vertical uniform accelerated motion, whose equations of motion are described below:

$x = x_{o}+v_{o}\cdot t\cdot \cos \theta$ (Eq. 1)

$y = y_{o} + v_{o}\cdot t \cdot \sin \theta +\frac{1}{2}\cdot g\cdot t^{2}$ (Eq. 2)

Where:

$x_{o}$ , $y_{o}$ - Coordinates of the initial position of the ball, measured in meters.

$x$ , $y$ - Coordinates of the final position of the ball, measured in meters.

$\theta$ - Angle of elevation, measured in sexagesimal degrees.

$v_{o}$ - Initial speed of the ball, measured in meters per square second.

$t$ - Time, measured in seconds.

If we know that $x_{o} = 0\,m$ , $y_{o} = 0\,m$ , $v_{o} = 22\,\frac{m}{s}$ , $\theta = 55^{\circ}$ , $g = -9.807\,\frac{m}{s}$ and $x = 40\,m$ , the following system of equations is constructed:

$40 = 12.618\cdot t$ (Eq. 1b)

$y = 18.021\cdot t -4.904\cdot t^{2}$ (Eq. 2b)

From (Eq. 1b):

$t = 3.170\,s$

And from (Eq. 2b):

$y = 7.847\,m$

Therefore, the ball makes the field goal.

In addition, we can calculate the components of the velocity of the ball when it reaches the field goal post by means of these kinematic equations:

$v_{x} = v_{o}\cdot \cos \theta$ (Eq. 3)

$v_{y} = v_{o}\cdot \cos \theta + g\cdot t$ (Eq. 4)

Where:

$v_{x}$ - Final horizontal velocity, measured in meters per second.

$v_{y}$ - Final vertical velocity, measured in meters per second.

If we know that $v_{o} = 22\,\frac{m}{s}$ , $\theta = 55^{\circ}$ , $g = -9.807\,\frac{m}{s}$ and $t = 3.170\,s$ , then the values of the velocity components are:

$v_{x} = \left(22\,\frac{m}{s} \right)\cdot \cos 55^{\circ}$

$v_{x} = 12.619\,\frac{m}{s}$

$v_{y} = \left(22\,\frac{m}{s} \right)\cdot \sin 55^{\circ} +\left(-9.807\,\frac{m}{s^{2}} \right)\cdot (3.170\,s)$

$v_{y} = -13.067\,\frac{m}{s}$

The magnitude of the final velocity of the ball is determined by Pythagorean Theorem:

$v =\sqrt{v_{x}^{2}+v_{y}^{2}}$ (Eq. 5)

Where $v$ is the magnitude of the final velocity of the ball.

If we know that $v_{x} = 12.619\,\frac{m}{s}$ and $v_{y} = -13.067\,\frac{m}{s}$ , then:

$v = \sqrt{\left(12.619\,\frac{m}{s} \right)^{2}+\left(-13.067\,\frac{m}{s}\right)^{2} }$

$v \approx 18.166\,\frac{m}{s}$

The magnitude of the velocity of the ball is approximately 18.166 meters per second.

The direction of the final velocity is given by this trigonometrical relation:

$\theta = \tan^{-1}\left(\frac{v_{y}}{v_{x}} \right)$ (Eq. 6)

Where $\theta$ is the angle of the final velocity, measured in sexagesimal degrees.

If we know that $v_{x} = 12.619\,\frac{m}{s}$ and $v_{y} = -13.067\,\frac{m}{s}$ , the direction of the ball is:

$\theta = \tan^{-1}\left(\frac{-13.067\,\frac{m}{s} }{12.619\,\frac{m}{s} } \right)$

$\theta = -45.999^{\circ} = 314.001^{\circ}$

The direction of motion is -45.999º or 314.001º.

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3 years ago

Two plastic geometric models shaped like a triangular prism and a triangular pyramid are each 16 cm tall. The base of each model

yKpoI14uk [10]

Answer:

320 cm difference

Step-by-step explanation:

<h3>Volume for Triangular prism: (1/2)(b)(h)(H)</h3><h3>Volume for Triangluar pyramid: (1/3)(1/2)(b)(h)(H)</h3>

480-160=320

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3 years ago

Please help i will give brainliest to the most accurate

Korolek [52]

Percent increase from 2000 to 2001 is 12% and from 2001 to 2002 is 12.6%. Thus period of 2001 to 2002 has higher increase percentage.

Solution:

Given that,

Total circulation of local newspaper in 2000 = 3250

Total circulation of local newspaper in 2001 = 3640

Total circulation of local newspaper in 2002 = 4100

As we can see 12% < 12.6%

So period of 2001 to 2002 has higher increase percentage.

6 0

3 years ago

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Parrots can develop cognitive issues as they get older. This may compromise their memory, ability to learn,

wlad13 [49]

Answer:

Part A: A control group would add in a datapoint that didn't receive any medicine, letting you know if the medicines actually work.

Part B: Split evenly. This makes sure you have enough data for each group.

Part C: By breed. Which sanctuary they come from wouldn't seriously impact their anatomy like which breed they are would.

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4 years ago