The equations standered form is y=-x^2/8-x/2-9/2
Answer:
16 m × 11 m
Step-by-step explanation:
The dimension of the gym is 20 m x 15 m. An outbound of 2m width is to be cut out from the gym to form the basketball court.
The original length of gym = 20 m and original width of gym = 15 m
2 m would be cut at both sides of the gym length for the outbound. Also 2 m would be cut at both sides of the gym width for the outbound. Therefore:
Length of basketball court = 20 m - (2 * 2m) = 20 m - 4 m = 16 m
Width of basketball court = 15 m - (2 * 2m) = 15 m - 4 m = 11 m
Therefore the dimensions of the basketball court is:
16 m × 11 m
Answer:
Two dimensional
Step-by-step explanation:
A single plane is a two dimensional platform
cubes and cylinders are both three dimensional objects.
B. False questions worth 3 ...
