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3 years ago

How many eighth notes are in each rhythm

Mathematics

2 answers:

kupik [55]3 years ago

7 0

Answer:

The first measure has 2 quarter notes, and each one gets one count. You can count them as "one two." The second measure has 4 eighth notes, written as pairs with their tails connected.

Step-by-step explanation:

RideAnS [48]3 years ago

4 0

Answer:

How many 8th notes are in each beat?

The first place to start with subdivisions of the beat is learning to feel the eighth note subdivision. Most music is in 4/4 time (see time signatures). That means 4 beats per bar/measure and each beat equals 1 quarter note. If we divide each of those quarter note beats in half, we get 8 eighth notes.

Step-by-step explanation:

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You downloaded a video game to your computer. You have a 60-minute free trial of the game. It takes 5 minutes to set up the game

vlada-n [284]

First you subtract 60-5 to see how much time you will have left to play.
60-5= 55
Then you divide 55/7 to see how many levels you can play for free.
55/7= I got 7.85 (rounded).
I hope its correct and sorry if its wrong! :)

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3 years ago

Read 2 more answers

Let f(x)= 3x-2 and g(x)=4x+1<br><br> Find (fog)(x)<br><br> Please help!!!

Lisa [10]

Answer:

f(g(x)) = 12x + 1

Step-by-step explanation:

Step 1: Define functions

f(x) = 3x - 2

g(x) = 4x + 1

Step 2: Find f(g(x))

f(g(x)) = 3(4x + 1) - 2

f(g(x)) = 12x + 3 - 2

f(g(x)) = 12x + 1

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4 years ago

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Rama09 [41]

103 represents how much money Victoria is depositing into the bank, or her principal.

The interest rate is 1.03, or 3%.

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4 years ago

Find the SUm of the infinite series.

givi [52]

I'll do problem 13 to get you started.

The expression $4\left(\frac{2^n}{7^n}\right)$ is the same as $4\left(\frac{2}{7}\right)^n$

Then we can do a bit of algebra like so to change that n into n-1

$4\left(\frac{2}{7}\right)^n\\\\4\left(\frac{2}{7}\right)^n*1\\\\4\left(\frac{2}{7}\right)^n*\left(\frac{2}{7}\right)^{0}\\\\4\left(\frac{2}{7}\right)^n*\left(\frac{2}{7}\right)^{1-1}\\\\4\left(\frac{2}{7}\right)^n*\left(\frac{2}{7}\right)^{1}*\left(\frac{2}{7}\right)^{-1}\\\\4*\left(\frac{2}{7}\right)^{1}\left(\frac{2}{7}\right)^n*\left(\frac{2}{7}\right)^{-1}\\\\\frac{8}{7}\left(\frac{2}{7}\right)^{n-1}\\\\$

This is so we can get the expression in a(r)^(n-1) form

a = 8/7 is the first term of the geometric sequence
r = 2/7 is the common ratio

Note that -1 < 2/7 < 1, which satisfies the condition that -1 < r < 1. This means the infinite sum converges to some single finite value (rather than diverge to positive or negative infinity).

We'll plug those a and r values into the infinite geometric sum formula below

S = a/(1-r)

S = (8/7)/(1 - 2/7)

S = (8/7)/(5/7)

S = (8/7)*(7/5)

S = 8/5

S = 1.6

------------------------

Answer in fraction form = 8/5

Answer in decimal form = 1.6

7 0

3 years ago

What is the difference between -4 and 6

LenaWriter [7]

Hey,

Answer:

2 and -2

Good luck :)

4 0

3 years ago