F(x) = - 55x + 330
The domain is the set of possible input-values, i.e. x-values.
You know that f(x) cannot bebigger than 330 not lower than zero, then construct the inequality:
0 ≤ f(x) ≤ 330
0 ≤ - 55x + 330 ≤ 330
Multilply by - 1 and change the inequality signs:
0 ≥ 55x - 330 ≥ -330
Add 330 to all the members
330 ≥ 55x ≥ 0
Divide by 55
6 ≥ x ≥ 0 => 0 ≤ x ≤ 6
The the possible x-values (practical domain) is all the real numbers between 0 and 6 inclusive.
Answer:
x = 6
Step-by-step explanation:
I think it's supposed to be
y = x² - 12x + 36
Set the equation equal to zero and solve...
0 = x² - 12x + 36
Now factor. What 2 numbers add to -12, and multiply to 36?
-6 and -6, so our factors are
0 = (x - 6)(x - 6)
So
0 = x - 6, then
6 = x
Answer:
a,2
Step-by-step explanation:
3×=4×-2
if ×=2
3(2)=4(2)-2
6=8-2
6=6
this is the answer I hope it will help you
f(x) is a quadratic equation with the x-side squared and a is positive which means that the graph of the function is a parabola facing up. The range of f(x) is given by {y|y ≥ k}, where k is the y-coordinate of the vertex.
, written in vertex form is
, where (h, k) = (-1, -11)
Therefore, range ={y|y ≥ -11}
