Answer:
Notice that 2 sheets of stamps will NOT be enough because 2 sheets have a total of 40 stamps and NOT 47
Step-by-step explanation:
Polynomial Degree:
3
3
Leading Term:
5
n
3
5
n
3
Leading Coefficient:
5
The slope of the line that passes through (5,−10) and ( 11 , − 12 ), in simplest form is: -1/3
<em><u>Recall:</u></em>
- The slope of a line passing across through two points can be calculated using:
<em><u>Given two points:</u></em>
(5,−10) and ( 11 , − 12 )
Slope (m) = -2/6
Slope (m) = -1/3
Therefore the slope of the line that passes through (5,−10) and ( 11 , − 12 ), in simplest form is: -1/3
Learn more about slope of a line on:
brainly.com/question/3493733
The answer is (2,0)
Explanation
So I’m gonna use substitution to help me solve this problem. I’m gonna solve for x.
X-y=2
+y. +y
X= y + 2
Now that we have solved for x we are going to plug it into the first equation!
Shown like this
Y+2 - 10y = 2
Then we solve it as a normal problem
So first we combine light terms
-9y+2=2
Then we isolate the variable
-9y+2=2
-2. -2
-9y = 0
Then we divide by -9 on both sides
-9y /-9 = 0 / -9
Y = 0
Now that we solved for y we plug it into one the equations to get the x value!
X - 0 = 2
X=2
The solution is (2,0)
I hope this helped you! Pls mark as brainliest
Answer:
1595 ft^2
Step-by-step explanation:
The answer is obtained by adding the areas of sectors of several circles.
1. Think of the rope being vertical going up from the corner where it is tied. It goes up along the 10-ft side. Now think of the length of the rope being a radius of a circle, rotate it counterclockwise until it is horizontal and is on top of the bottom 20-ft side. That area is 3/4 of a circle of radius 24.5 ft.
2. With the rope in this position, along the bottom 20-ft side, 4.5 ft of the rope stick out the right side of the barn. That amount if rope allows for a 1/4 circle of 4.5-ft radius on the right side of the barn.
3. With the rope in the position of 1. above, vertical and along the 10-ft left side, 14.5 ft of rope extend past the barn's 10-ft left wall. That extra 14.5 ft of rope are now the radius of a 1/4 circle along the upper 20-ft wall.
The area is the sum of the areas described above in numbers 1., 2., and 3.
total area = area 1 + area 2 + area 3
area of circle = (pi)r^2
total area = 3/4 * (pi)(24.5 ft)^2 + 1/4 * (pi)(4.5 ft)^2 + 1/4 * (pi)(14.5 ft)^2
total area = 1414.31 ft^2 + 15.90 ft^2 + 165.13 ft^2
total area = 1595.34 ft^2
