The solution to the equation r(1 - 2cosФ) = 1 is given as x² + y² - 4x√(x² + y²) + 4x² = 1
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
In polar form:
r = √(x² + y²) and cosФ = x / √(x² + y²)
Hence:
r(1 - 2cosФ) = 1
√(x² + y²) [1 - 2(x / √(x² + y²))] = 1
√(x² + y²) - 2x = 1
Take square of both sides:
x² + y² - 4x√(x² + y²) + 4x² = 1
The solution to the equation r(1 - 2cosФ) = 1 is given as x² + y² - 4x√(x² + y²) + 4x² = 1
Find out more on equation at: brainly.com/question/2972832
#SPJ1
Okay! In order to find 8 groups of .32 you'd simply divide them. So:
[.32 ÷ 8] = .04
To check you multiply:
[8 x .04] = .32.
The answer is .04
Answer:
9x^2 - 3x - 2, R -7.
Step-by-step explanation:
x - 5) 9x^3 - 48x^2 + 13x + 3(9x^2 - 3x - 2 <---- Quotient.
9x^3 - 45x^2
- 3x^2 + 13x
-3x^2 + 15x
-2x + 3
-2x + 10
-7 <----- Remainder