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goldenfox [79]
2 years ago
10

Which pair of functions are inverses of each other?  A. f(x) = \sqrt[3]{{6x}}f(x)= 3 6x​ and g(x) = {\left( {\frac{x}{6}} \righ

t)^3}g(x)=( 6 x​ ) 3  B. f(x) = 10x – 5 and g(x) = \frac{{x + 5}}{{10}}g(x)= 10 x+5​ C. f(x) = \frac{4}{x} - 3f(x)= x 4​ −3 and g(x) = \frac{{x + 3}}{4}g(x)= 4 x+3​ D. f(x) = \frac{x}{8} + 3f(x)= 8 x​ +3 and g(x) = 8x – 3​

Mathematics
1 answer:
Simora [160]2 years ago
6 0

Answer:

the answer is B

Step-by-step explanation:

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Divide -2x^3-5x^2+4x+2 by x+2
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<u>Answer</u><u>: </u>

The correct option is C.  -2x^2-x+6, R(-10)

<u> Explanation: </u>

<u>Given:</u>

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Divider =(x+2)

<u>Solution</u>:

Now by using the division method , we will find out the quotient and remainder of the given equation  

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Which shows the correct substitution of the values a, b, and c from the equation 0 = – 3x2 – 2x + 6 into the quadratic formula?
lbvjy [14]

Answer:

x = StartFraction negative

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It can still be written as

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