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goldenfox [79]
2 years ago
10

Which pair of functions are inverses of each other?  A. f(x) = \sqrt[3]{{6x}}f(x)= 3 6x​ and g(x) = {\left( {\frac{x}{6}} \righ

t)^3}g(x)=( 6 x​ ) 3  B. f(x) = 10x – 5 and g(x) = \frac{{x + 5}}{{10}}g(x)= 10 x+5​ C. f(x) = \frac{4}{x} - 3f(x)= x 4​ −3 and g(x) = \frac{{x + 3}}{4}g(x)= 4 x+3​ D. f(x) = \frac{x}{8} + 3f(x)= 8 x​ +3 and g(x) = 8x – 3​

Mathematics
1 answer:
Simora [160]2 years ago
6 0

Answer:

the answer is B

Step-by-step explanation:

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6 0
2 years ago
Solve for m: 18d + 2m + 9k < 5k + 10.
lions [1.4K]
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subtract 9k from both sides

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factor out the common term 2

divide both sides by 2

cancel 2 and now simplify brackets

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3 0
3 years ago
Is it, A, B, C, Or D?
trasher [3.6K]

Answer:

C

Step-by-step explanation:

6(2m+5n)

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Jacob had multiplied 6 to 2m right which is 12m but multiplied 6 and 5n wrong as he thought it was 11n yet it is 30n.

4 0
2 years ago
Rewrite in simplest terms -5(3u + 1) + 10
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Answer:

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