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3 years ago

8

True or false: Removing the parenthesis from will change the result.

2 answers:

Alchen [17]3 years ago

6 0

Answer:

True

Step-by-step explanation:

In a equation with parenthesis it is VERY important to never take them out of the equation. The only reason for that is that the parentthesis are signaling you to solve what is in the parentthesis first. And if you where to move the parenthesis out your answer would be totally different. Hope this helped. (Brainliest?)

egoroff_w [7]3 years ago

4 0

Answer:

true

Step-by-step explanation:

the steps won't be the same

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Solve: Six and three sevenths minus one and three sixths equals blank

Natali5045456 [20]

Answer:

4 13/16

Step-by-step explanation:

6 3/7 - 1 3/6 =

270/42 - 63/42 = 207/42 = 4 39/48 = 4 13/16

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2 years ago

Rewrite this standard form quadratic equation into vertex form by completing the square. Upload your work here to show your thin

Alex787 [66]

Solution :

Given the equation :

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$n = \left(\frac{b}{2}\right)^2$

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3 0

3 years ago

If w varies inversely with the square root of t and w = 5 when t = 49,

VARVARA [1.3K]

Answer:

x=k/y

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5 0

3 years ago

How do i do 3 part a ?

WINSTONCH [101]

In general the binomial expansion is

$(a+b)^n = {n \choose 0} a^0 b^n + {n \choose 1} a^1 b^{n-1} + {n \choose 2} a^2 b^{n-2} + ... + {n \choose n} a^n b^0$

So in our case, because we want ascending powers of x we'll write,

$(-3x + 1)^{11} = {11 \choose 0} (-3x)^0 1^{11} + {11 \choose 1} (-3x)^{1} 1^{10} + {11 \choose 2} (-3x)^{2} 1^9 + {11 \choose 3 } (-3x)^3 1^8 + ...$

We need to calculate the binomial coefficients:

${11 \choose 0} = 1$

${11 \choose 1} = 11$

${11 \choose 2} = \dfrac{11 \times 10}{2} = 55$

${11 \choose 3} = \dfrac{11 \times 10 \times 9}{3 \times 2} = 165$

$(-3x+1)^{11} = 1 (-3x)^0 1^{11} + 11(-3x)^{1} 1^{10} + 55 (-3x)^2 1^{9} + 165 (-3x)^3 1^8 + ...$

$(1-3x)^{11} = 1 -33 x + 495 3x^2 - 4455 x^3+ ...$

6 0

3 years ago

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Andreyy89

The answer is 1/6 because 1 /2 × 1/3 =1/6

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3 years ago

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