HELLLPPP!

1 answer:

6 0

The correct answer is this one: "<span>B) The graphs open downward. " Negative quadratic functions will give you a downward graph.
</span>
The equations
y = -1/2x^2 + 2
y = -2x^2 + 3
y = -3/4x^2
<span>y = -4/5x^2 - 5
</span>
are all negative. So they are facing downward.

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if there are four trucks parked in line and after the first truck each truck weighed 2 more tons than the one before. They all w

algol13

Each truck weighs five tons.

1st truck: n
2nd truck: n + 2
3rd truck: n + 4
4th truck: n + 6

n + n + 2 + n + 4 + n + 6 = 32
4n + 12 = 32
- 12 - 12
--------------------
4n = 20
---- ------
4 4

n = 5

6 0

4 years ago

40Points? CORRECT answer please

irina [24]

Answer:

Step-by-step explanation:

$f(t)=2(0.4)^t$

f(-2) → put t = -2 to the equation of the function:

$f(-2)=2(0.4)^{-2}=2\left(\dfrac{4}{10}\right)^{-2}=2\left(\dfrac{2}{5}\right)^{-2}$

Use $a^{-n}=\left(\dfrac{1}{a}\right)^n$

$f(-2)=2\left(\dfrac{5}{2}\right)^2=2\left(\dfrac{25}{4}\right)=\dfrac{25}{2}=12.5$

3 0

3 years ago

What is the area of the square adjacent to the third side of the triangle?

lana66690 [7]

Answer:

The area of the square adjacent to the third side of the triangle is 11 units²

Step-by-step explanation:

We are given the area of two squares, one being 33 units² the other 44 units². A square is present with all sides being equal, and hence the length of the square present with an area of 33 units² say, should be x² = 33 - if x = the length of one side. Let's make it so that this side belongs to the side of the triangle, to our convenience,

x² = 33,

x = $\sqrt{33}$ .... this is the length of the square, but also a leg of the triangle. Let's calculate the length of the square present with an area of 44 units². This would also be the hypotenuse of the triangle.

x² = 44,

x = $\sqrt{44}$ .... applying pythagorean theorem we should receive the length of a side of the unknown square area. By taking this length to the power of two, we can calculate the square's area, and hence get our solution.