Show Step by step for solving <br><br>-6(n-3) = 5(4-n)

an insulated tote bag has a volume of 972 cubic inches. if the base of the tote bag is a square with an area of 81 square inches

xxMikexx [17]

Answer: The height is 12 inches.

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Volume: area x height

Replacing with the values given:

972 cubic inches = 81 square inches x h

Solving for h (height)

972/81 = h

12 inches =h

The height is 12 inches.

Feel free to ask for more if needed or if you did not understand something.

3 0

3 years ago

3. The cost of the city permits needed to build this building is 150,000 no matter how many floors with

natima [27]

Answer:

$P(x) = 150000$

$Slope = 0$

Step-by-step explanation:

Given

$Cost = 150000$

Solving (a): The cost function:

From the given parameter, it shows that the number of floor has no effect on the floors.

So, represent the floors with x.

The cost function is:

$P(x) = 150000$

Solving (b): The slope and its interpretation

A function is represented as:

$f(x) = b + mx$

Where:

$m=slope$

By comparing: $f(x) = b + mx$ to $P(x) = 150000$

$m = 0$

So:

$Slope = 0$

<em>What it means is that, no matter the number of floors, the cost remains unchanged.</em>

4 0

3 years ago

What geometric term describes part of a line that has one endpoint?

Fudgin [204]

A ray. it has line stopping point and goes on forever in the other direction.

8 0

3 years ago

(-3)³ + (-4)² - (-2)³

AleksAgata [21]

Answer:

$=-3$

Step-by-step explanation:

$\left(-3\right)^3+\left(-4\right)^2-\left(-2\right)^3\\Follow\:the\:PEMDAS\:order\:of\:operations\\\mathrm{Calculate\:exponents}\:\left(-3\right)^3\::\quad -27\\\left(-3\right)^3\\\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=-a^n,\:\mathrm{if\:}n\mathrm{\:is\:odd}\\\left(-3\right)^3=-3^3=-27\\=-27+\left(-4\right)^2-\left(-2\right)^3\\\mathrm{Calculate\:exponents}\:\left(-4\right)^2\::\quad 16\\\left(-4\right)^2$

$\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=a^n,\:\mathrm{if\:}n\mathrm{\:is\:even}\\\left(-4\right)^2=4^2=16\\=-27+16-\left(-2\right)^3\\\mathrm{Calculate\:exponents}\:\left(-2\right)^3\::\quad -8\\\left(-2\right)^3\\\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=-a^n,\:\mathrm{if\:}n\mathrm{\:is\:odd}\\\left(-2\right)^3=-2^3=-8\\=-27+16-\left(-8\right)\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:-27+16-\left(-8\right)\::\quad -3\\-27+16-\left(-8\right)$