Workout the probability that spinner A lands on 2 and spinner b does not land on b
1 answer:
Spinner diagram isn't attached. A related spinner diagram has been attached below to provide an hypothetical solution to the problem
Answer:
4 / 15
Step-by-step explanation:
For the numbered spinner :
P(landing on 2) = required outcome / Total possible outcomes
Total possible outcomes = (1, 2, 3) = 3
Required outcome = (1) = 1
P(landing on 2) = 1 /3
Lettered spinner :
P(does not land on b)
Total possible outcomes = (A, B, C, D, E)
Required outcome = (a, c, d, e)
P(does not land on b) = 4 / 5
Hence,
P(lands on 2, does not land on b) in this scenario is :
1/3 * 4/5 = 4 / 15
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Answer:
The 99% confidence interval of the population mean for the weights of adult elephants is between 12,475 pounds and 12,637 pounds.
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 10 - 1 = 9
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of . So we have T = 3.25
The margin of error is:
M = T*s = 3.25*25 = 81
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 12,556 - 81 = 12,475 pounds
The upper end of the interval is the sample mean added to M. So it is 12,556 + 81 = 12,637 pounds.
The 99% confidence interval of the population mean for the weights of adult elephants is between 12,475 pounds and 12,637 pounds.