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Leni [432]
3 years ago
5

The expression sinx + cotx cosx can be simplified to___. A. cotx B. cscx C. cosx sinx D. secx

Mathematics
2 answers:
Sav [38]3 years ago
7 0
\sin x+\cot x\cos x=\sin x+\dfrac{\cos x}{\sin x}\cos x=\dfrac1{\sin x}(\sin^2x+\cos^2x)=\csc x
gregori [183]3 years ago
7 0

Answer:

Solution-

∵ cotx = (cosx÷sinx)

∴ The given expression can be written as

sinx + cotx·cosx = sinx + ( cosx÷ sinx).cosx

⇒sinx +(cosx)²÷sinx = [ (sinx)² + (cosx)²] ÷ sinx

⇒ 1÷ sinx = cosecx = cscx

using the identity (sinx)²+(cosx)²=1

∴ option B is correct.


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What is the slope of the line through the points (4,2) and (-16,-6)
Maslowich

Answer:

2 / 5.

Step-by-step explanation:

The slope is the rise over the run.

In this case, the rise is 2 - (-6) = 2 + 6 = 8.

The run is 4 - (-16) = 4 + 16 = 20.

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Hope this helps!

7 0
4 years ago
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he Thomas Supply Company Inc. is a distributor of gas-powered generators. As with any business, the length of time customers tak
WINSTONCH [101]

Answer:

30.5 ; 49 ; 27 ; 50 ; 45

Step-by-step explanation:

Determine the first and third quartiles. Determine the second decile and the eighth decile. Determine the 67th percentile

Given the ordered data :

13 13 13 20 26 27 29 32 34 34 35 35 36 37 38 41 41 41 42 44 46 47 48 50 53 55 56 62 67 82

Sample size, n = 30

The first quartile ;Q1

Q1 = 1/4(n+1)th term

Q1 = 31/4 = 7.75th term

Q1 = (29+32)/2

Q1 = 30.5

Q3 ;

Q3 = 3/4(n+1)th term

Q3 = 3(31)/4 = 23.25 th term

Q3 = (48 + 50) /2 = 49

2nd decile :

0.2 * (nth term

0.2 * 30 = 6th term = 27

8th decile :

0.8 * 30 = 24 th term

= 50

67th percentile :

0.67 * (n+1)th term

0.67 * 31 = 20.77

= (44 + 46) / 2

= 45

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3 years ago
How do you write 2x in radical form
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Simplify 4x+5/6x^2-x-12 subtract 5x/6x^2-x-12
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<span>4x+5/6x^2-x-12 - (5x/6x^2-x-12)
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<span>
answer

       -x + 5
---------------------
</span>  (2x - 3)(3x +4)
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