The surface area of the sphere is:
A = 4 * pi * r ^ 2
Deriving we have:
A '= 8 * pi * r * r'
We clear the speed:
r '= A' / (8 * pi * r)
Substituting values:
r '= 24 / (8 * pi * 3)
r '= 1 / pi inch / sec
Then, the volume of the sphere is:
V = (4/3) * (pi) * (r ^ 3)
Deriving we have:
V '= (3) * (4/3) * (pi) * (r ^ 2) * (r')
Substituting values:
V '= (3) * (4/3) * (pi) * (3 ^ 2) * (1 / pi)
Rewriting:
V '= (4) * (9)
V '= 36 inch3 / sec
Answer:
the volume of the ice is changing at 36 inch3 / sec at that moment
4x^2+ 8xy - 60y^2 =48x^3y^3
Answer:
6 ounces
Step-by-step explanation:
Let x = the number of ounces of the 15% alcohol solution needed to be mixed with the 4 ounces of 20% alcohol solution to obtain the 17% alcohol solution.
After converting the percentages to their decimal equivalents, set up the necessary equation as follows:
0.15x+0.20(4) = (x+4)(0.17) Simplify and solve for x.
0.15x+0.8 = 0.17x+0.68 Subtract 0.15x from both sides.
0.8 = 0.02x+0.68 Now subtract 0.68 from both sides.
0.12 = 0.02x Finally, divide both sides by 0.02
x = 6
You need to mix 6 ounces of 15% alcohol solution with 4 ounces of 20% alcohol solution to obtain 10 (x+4)ounces of 17% alcohol solution.
9514 1404 393
Answer:
A, B, D
Step-by-step explanation:
The "opposite" of a number is that number with its sign changed.
__
- The opposite of zero is zero.
- A number and its opposite are located the same distance from zero on a number line.
- The opposite of a negative number is always a positive number.
Answer:
∠6 > ∠3 is TRUE.
Step-by-step explanation:
We know that acute angle is less than 90 degree while obtuse angle is more than 90 degree. By looking at the given angles, we can easily determine which angle is obtuse or acute. then we can decide which angle is bigger to find the answer.
∠10 > ∠7
FALSE;
Because∠10 is acute while ∠7 is obtuse.
------------
∠6 > ∠3
TRUE;
Because∠3 is acute while ∠6 is obtuse.
------------
∠9 > ∠11
FALSE;
Because∠9 is acute while ∠11 is obtuse.
------------
∠8 > ∠11
FALSE;
Because∠8 is acute while ∠11 is obtuse.
------------