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3 years ago

What is the slope of the line through the points (4,2) and (-16,-6)

Mathematics

2 answers:

Maslowich3 years ago

7 0

Answer:

2 / 5.

Step-by-step explanation:

The slope is the rise over the run.

In this case, the rise is 2 - (-6) = 2 + 6 = 8.

The run is 4 - (-16) = 4 + 16 = 20.

So, the slope is 8 / 20 = 4 / 10 = 2 / 5.

Hope this helps!

Firlakuza [10]3 years ago

6 0

Answer:

the slope of the line that goes through (4,2) and (-16,-6) is 2/5

m= 2/5

Step-by-step explanation:

in order to find the slope we use the ∆y/∆x which is really the change in y over the change in x.

so all you have to do is find your y's and X's.

your y's are -6 and 2

your X's are -16 and 4

now in order to find the change in y and x you subtract your y's and x'x

the formula for this is:

∆y/∆x = y1-y2/x1-x2= (m aka the slope)

y1 is -6

and y2 is 2

-6 - 2 = -8

now do the X's

X1 is -16

and X2 is 4

-16 - 4 = -20

put that in fraction form and it's -8/-20

simplify that you get 2/5

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If the parent function f(x) = x^2 is fatter translated 11 units to the left, then translated 5 units down, write the resulting f

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The quadratic function given by:

$f(x)=a(x-h)^2+k, \ \ \ a\neq 0$

is in vertex form. The graph of $f$ is a parabola whose axis is the vertical line $x=h$ and whose vertex is the point $(h, k)$ . So:

To translate the graph of a function to the right, left, upward or downward we have:

$For \ a \ positive \ real \ number \ c. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:\\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ g(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ g(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{right}: \\ g(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{left}: \\ g(x)=f(x+c)$

By knowing this things, we can solve our problem as follows:

FIRST.

Translating 11 units to the left:

$g(x)=f(x+11) \\ \\ \therefore g(x)=(x+11)^2$

Then translating 5 units down:

$g(x)=f(x)-c \\ \\ \therefore g(x)=(x+11)^2-5$

Since the new function is fatter, the factor we need to multiply the term $(x+11)^2$ must be less than 1, to make the graph fatter. So, according to our options, there are two factors 1/2 and 2.