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3 years ago

Pleaseee helpp answer correctly !!!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

Shtirlitz [24]3 years ago

3 0

Answer:

BD = 30

Step-by-step explanation:

if it is a square, than all sides are equal

so if AC = 30, then BD = 30 as well

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Hugo and Viviana work in an office with ten other coworkers. Out of these 12 workers, their boss needs to choose a group of five

7nadin3 [17]

Answer: 792

Step-by-step explanation:

Given : Hugo and Viviana work in an office with ten other coworkers.

Out of these 12 workers, their boss needs to choose a group of five to work together on a project.

The combination of n thing taking m at a time is given by :-

$C(n;m)=\dfrac{n!}{m!(n-m)!}$

Then, the number of different working groups of five the boss can choose :-

$C(12;5)=\dfrac{12!}{5!(12-5)!}\\\\=792$

Hence, the number of different working groups of five the boss can choose = 792.

3 0

3 years ago

A coin is tossed 10 times. True or false, and explain: (a) The chance of getting 10 heads in a row is 1/1,024. (b) Given that th

Llana [10]

Answer:

a and b both are true.

Step-by-step explanation:

Given : A coin is tossed 10 times.

To find : True or false, and explain ?

Solution :

(a) The chance of getting 10 heads in a row is $\frac{1}{1024}$

Coin has two face head and tail.

The probability of getting head is $P(H)=\frac{1}{2}$

The probability of getting 10 heads in a row is

$P=(P(H))^{10}$

$P=(\frac{1}{2})^{10}$

$P=\frac{1}{1024}$

The chance of getting 10 heads in a row is $\frac{1}{1024}$ is true.

(b) Given that the first 9 tosses were heads, the chance of getting 10 heads in a row is $\frac{1}{2}$ .

The probability of getting 10 heads in a row is $P_1=(\frac{1}{2})^{10}$

The probability of getting 9 tosses were heads is $P_2=(\frac{1}{2})^{9}$

Given that the first 9 tosses were heads, the chance of getting 10 heads in a row is given by,

$P=\frac{P_1}{P_2}$

$P=\frac{(\frac{1}{2})^{10}}{(\frac{1}{2})^{9}}$

$P=(\frac{1}{2})^{10-9}$

$P=\frac{1}{2}$

Given that the first 9 tosses were heads, the chance of getting 10 heads in a row is $\frac{1}{2}$ is true.

3 0

4 years ago

Point C represents the center of the sphere.

nexus9112 [7]

Answer:

diameter

Step-by-step explanation:

5 0

4 years ago

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The cheerleaders are practicing a dance routine in which all 36 of them need to be in a triangular formation. there will be two

dimulka [17.4K]

If you start with 1 cheerleader in row A, then you'll have 3 cheerleaders in row B (add on 2), and then 5 cheerleaders for row C (add on another 2), etc etc.

Note how: 1+3+5 = 4+5 = 9 which is a perfect square. Also note that 36 is a perfect square.

Rule: The sum of the first positive n odd numbers is going to be equal to n^2. In the example of adding the first three odd numbers (1,3,5), we have n^2 = 3^2 = 9 as the sum

So as you can see, we'll have n = 6 rows because n^2 = 6^2 = 36 and

1+3+5+7+9+11 = 36

which is the sum of the first six positive odd numbers. So we'll have 1 cheerleader in row A, 3 in row B, 5 in row C, 7 in row D, 9 in row E, 11 in row F to have 6 rows total.

3 0

3 years ago

Complete the solution of the equation. Find

Anarel [89]

Y=-2 is the correct answer

8 0

3 years ago

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