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gogolik [260]
3 years ago
8

Colton has n nickels and d dimes. He has no more than $2 worth of coins altogether. Write this situation as an inequality.

Mathematics
1 answer:
lisov135 [29]3 years ago
4 0

Answer:

Step-by-step explanation:

Represent the number of nickels and dimes by n and d.

The value of these nickels and dimes will be $0.05n + $0.10d ≤ $2.00.

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Given a circle with a radius of 6, what the the length of an arc measuring 30 degrees
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\bf \textit{arc's length}\\\\
s=\cfrac{\theta \pi r}{180}\quad 
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\qquad degrees\\
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r=6\\
\theta =30
\end{cases}\implies s=\cfrac{30\cdot \pi \cdot 6}{180}\implies s=\pi
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The height h is greater than 2.5 meters.<br> Write an inequality for the word sentence
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H > 2.5

Step-by-step explanation:

Greater = >

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Lucy deposits $7000 into an account that pays simple interest at a rate of 3% per year. How much interest will she be paid in th
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3 years ago
I don't get it and I have tried it multiple ways
jasenka [17]

9514 1404 393

Answer:

  9350 m²

Step-by-step explanation:

There are several ways you can go at this. Here are 3 of them:

  1. along an extension of the lower right vertical edge, divide the figure into a rectangle and a right triangle.
  2. between the upper left corner and the inside corner at lower right draw a diagonal line to divide the figure into a trapezoid and a triangle.
  3. subtract the area of the trapezoid at the right from the area of the bounding rectangle

__

The relevant formulas for area are ...

  rectangle: A = LW . . . . . . . . . . . length times width

  trapezoid: A = (1/2)(b1 +b2)h . . . b1, b2 are the bases, h is the height

  triangle: A = (1/2)bh . . . . . . . . . . . b is the base, h is the height

__

Here's what those computations look like:

1. rectangle: 60m wide by 80 m high = 4800 m².

  right triangle: base 190-60 = 130 m; height = 80-10 = 70 m.

     area = (1/2)(130 m)(70 m) = 4550 m²

  figure area = 4800 m² +4550 m² = 9350 m² . . . . area of figure

__

2. The trapezoid has bases of 80 m and 10 m, and a height of 60 m. Its area is ...

  A = (1/2)(80 m +10 m)(60 m) = 2700 m²

The triangle has a base of 190 m and a height of 80-10 = 70 m. Its area is ...

  A = (1/2)(190 m)(70 m) = 6650 m²

Then the total area is 2700 m² +6650 m² = 9350 m² . . . total area

__

3. The bounding rectangle is 190 m by 80 m, so its area is ...

  A = LW = (190 m)(80 m) = 15200 m²

The (negative) trapezoid at right has bases of 10 m and 80 m, and a width of 190-60 = 130 m. Its area is ...

  A = (1/2)(10 m +80 m)(130 m) = 5850 m²

The area of the figure is the difference between these:

  figure area = 15200 m² -5850 m² = 9350 m² . . . figure area

7 0
3 years ago
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