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larisa [96]
2 years ago
7

Find the angle represented by x rounded to the nearest tenth of a degree

Mathematics
1 answer:
Zinaida [17]2 years ago
8 0

Answer:

<h3>x = 49.6°</h3>

Step-by-step explanation:

Find the image attached;

From the image;

opposite side = 16

Hypotenuse = 21

Angle of inclination = x

Using the SOH identity

sinx = opposite/hypotenuse

sin x = 16/21

sin x = 0.7619

x = arcsin 0.7619

x = 49.6° (to the nearest tenth of a degree)

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Answer:

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Step-by-step explanation:

The object is 'in the air' for all t such that h> 0.  We need to find the roots of h = -16t^2 + 108t - 25 = 0.  From the graph we see that both t values are positive.  Once we find them, we subtract the smaller t from the larger t, which results in the length of time the object is in the air.

Use the quadratic formula to find the roots of h(t).  The coefficients of t are {-16, 108, -25}, and so the discriminant b^2 - 4ac is

108² - 4(-16)(-25) = 11664 - 1600 = 10064, whose square root is 100.32.

Then the quadratic formula x = (-b ± √[b² - 4ac)/(2a) becomes

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t = ---------------------- = --------------------- = 3.375 ± 3.135

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or t = 6.51 or t = 0.24  (both times expressed in seconds).

So, again, the object is in the air on the time interval (0.24 sec, 6.51 sec)

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3 years ago
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Vladimir [108]

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Step-by-step explanation:

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