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3 years ago

Yo, i really need help with this question

Mathematics

1 answer:

jok3333 [9.3K]3 years ago

8 0

Answer:

Second graphic from the top

Step-by-step explanation:

Formula for g(x) is g(x) = (1/2) · x∧2

when we replace x= 10 in the formula we get

g(10) = (1/2) · 10∧2 = (1/2) · 100 = 50

God with you!!!

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2x + y = 7<br> -2x - y = 6<br> Solve systems of equations by substitution

ehidna [41]

Answer:

No solution.

Step-by-step explanation:

2x + y = 7

-2x - y = 6

From the first equation:

y = 7 - 2x

Plug this into the second equation:

-2x - (7 - 2x) = 6

-2x + 2x = 6 + 7

0 = 13

this doesn't make sense so theer is:

No solution.

4 0

2 years ago

Is 10/9 closer to 0 1/2 or 1

Viktor [21]

The answer is the number 1.

5 0

3 years ago

Which equation would you use to find how high the bird is flying?

damaskus [11]

Answer:

The first one

Step-by-step explanation:

An easy way is SOH CAH TOA

SOH is that you use sine if you there is the opposite (in this case the question mark) and hypotenuse (the diagonal line)

CAH is that you use cosine for the adjacent side (1100) and the hypotenuse.

TOA is using tangent for the opposite and adjacent side.

To fine the question mark, you would use tangent. And plug in the given (1100 for the adjacent). So tan45 = x/1100.

If you need more help or clarification, let me know!

6 0

3 years ago

How many solutions does this equation have?<br><br> –4j = –8j + 4j

emmainna [20.7K]

Answer:

Your Mom just remember your a di*k and thats why your parents burned your birth certifcate

Step-by-step explanation:

if your gonna do that to me, remember i have copy and paste<3.

5 0

3 years ago

You have D dollars to buy fence to enclose a rectangular plot of land (see figure at right). The fence for the top and bottom co

alex41 [277]

The perimeter of the rectangular plot of land is given by the expression below

$P=2x+2y$

On the other hand, since the available money to buy fence is D dollars,

$\begin{gathered} D=4(2x)+3(2y) \\ \Rightarrow D=8x+6y \\ D\rightarrow\text{ constant} \end{gathered}$

Furthermore, the area of the enclosed land is given by

$A=xy$

Solving the second equation for x,

$\begin{gathered} D=8x+6y \\ \Rightarrow x=\frac{D-6y}{8} \end{gathered}$

Substituting into the equation for the area,

$\begin{gathered} A=(\frac{D-6y}{8})y \\ \Rightarrow A=\frac{D}{8}y-\frac{3}{4}y^2 \end{gathered}$

To find the maximum possible area, solve A'(y)=0, as shown below

$\begin{gathered} A^{\prime}(y)=0 \\ \Rightarrow\frac{D}{8}-\frac{3}{2}y=0 \\ \Rightarrow\frac{3}{2}y=\frac{D}{8} \\ \Rightarrow y=\frac{D}{12} \end{gathered}$

Therefore, the corresponding value of x is

$\begin{gathered} y=\frac{D}{12} \\ \Rightarrow x=\frac{D-6(\frac{D}{12})}{8}=\frac{D-\frac{D}{2}}{8}=\frac{D}{16} \end{gathered}$ <h2>Thus, the dimensions of the fence that maximize the area are x=D/16 and y=D/12.</h2><h2>As for the used money,</h2> $\begin{gathered} top,bottom:\frac{8D}{16}=\frac{D}{2} \\ Sides:\frac{6D}{12}=\frac{D}{2} \end{gathered}$ <h2>Half the money was used for the top and the bottom, while the other half was used for the sides.</h2>

7 0

11 months ago