−7x−3≤ 25

Select all pairs of numbers that have a least common multiple of 30.

ddd [48]

5 and 6 and 3 and 10, the pairs of numbers that have a least common multiple of 30.

<u>Step-by-step explanation:</u>

Case 1: LCM (3, 6)

Prime factorization of 3: $1 \times 3$

Prime factorization of 6: $2 \times 3$

Using all prime numbers found as often as each occurs most often we take

$2 \times 3=6$

Therefore LCM (3, 6) = 6.

Case 2: LCM (5, 6)

Prime factorization of 5: $1 \times 5$

Prime factorization of 6: $2 \times 3$

Using all prime numbers found as often as each occurs most often we take

$5 \times 2 \times 3=30$

Therefore LCM (5, 6) = 30

Case 3: LCM (3, 10)

Prime factorization of 3: $1 \times 3$

Prime factorization of 10: $2 \times 5$

Using all prime numbers found as often as each occurs most often we take

$5 \times 2 \times 3=30$

Therefore LCM (3, 10) = 30

Case 4: LCM (5, 10)

Prime factorization of 5: $1 \times 5$

Prime factorization of 10: $2 \times 5$

Using all prime numbers found as often as each occurs most often we take

$5 \times 2=10$

Therefore LCM (5, 10) = 10

8 0

3 years ago

Expression is 6 x to the second power gives the surface area of a cube in the expression x to the third power

OLEGan [10]

I honestly dont know but try mathpapa

6 0

3 years ago

Rational numbers<br> Is 17.156 a rational number

ella [17]

Answer:

yes

Step-by-step explanation:

5 0

3 years ago

A polynomial with integer coefficients is of the form \[x^4 + a_3 x^3 + a_2 x^2 + a_1 x + 18.\]You are told that the integer $r$

Pepsi [2]

Answer:-2 and 2

Step-by-step explanation:

Since the polynomial given [x^4 + a_3 x^3 + a_2 x^2 + a_1 x + 18.\] is divisible by (x - r)^2, this means that (x - r)^2 is a factor of the polynomial just like 4 is divisible by 2, we say 2 is a factor.

Since (x - r)^2 is a factor, we equate the factor to zero in order to get the 'x' variable.

(x - r)^2 =0

Taking square root of both sides gives x-r =0 i.e x=r

Substituting x=r into the polynomial to get 'r' we have r^4 + a_3 r^3 + a_2 r^2 + a_1r + 18=0.

Let a be 1 since the coefficients are integers

We then have Answer:

Step-by-step explanation:

Since the polynomial given [x^4 + a_3 x^3 + a_2 x^2 + a_1 x + 18.\] is divisible by (x - r)^2, this means that (x - r)^2 is a factor of the polynomial just like 4 is divisible by 2, we say 2 is a factor.

Since (x - r)^2 is a factor, we equate the factor to zero in order to get the 'x' variable.

(x - r)^2 =0

Taking square root of both sides gives x-r =0 i.e x=r

Substituting x=r into the polynomial to get 'r' we have r^4 + r^3 + r^2 + r + 18=0.

Factorizing this, possible value of r will be -2 and 2

5 0

3 years ago

Which expression does not belong with the other three? explain your answer

saul85 [17]

-6 is the expression that doesn't belong because it's the only true negative number. Absolute value signs (||) indicate that the number will be positive, even if it has a negative sign. So, 6, |6|, and |-6| are all equal.

8 0

3 years ago

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