
Expanding the left side gives

which gives two solutions,

and

. But if

, then

, but this number isn't real, so

is an extraneous solution. Meanwhile if

, you get

, so this solution is correct.
"Potential solutions" might refer to both possibilities, but there is only one actual (real) solution.
Answer:
27.5 minutes
Step-by-step explanation:
Using,
R/R' = 2ᵃ/ᵇ------------------ Equation 1
From the equation,
R = mass of Element X before radioactive decay, R' = mass of element X after radioactive decay, a = Time taken, b = half life.
Given: R = 870 grams, R' = 154 grams, b = 11 minutes.
Substitute these values into equation 1
870/154 = 2ᵃ/¹¹
(870/154)¹¹ = 2ᵃ
Solve for a
2ᵃ = (5.649)¹¹
2ᵃ = 187061.26
Taking the logarithm of both side,
Log2ᵃ = Log(187061.26)
⇒ a = log(187061.26)/log2
a = 8.272/0.301
a = 27.5 minutes
X
--- × 56 =18
100
56x = 18×100
× = 18 × 100
- - - - - - -
56
X = 32.14%
Answer:
A = 2
D = 1
B = 4
C = 3
Step-by-step explanation:
Height of water in bathtub is a function of water in bathtub.
P(t) = w ; t = time ; w = height of water.
A: P (0)=0 ; At time, t = 0 ; height of water = 0, there is no water on bathtub
2: The bathtub starts out with no water.
D: P (20) = 0 ; At time, t = 20 ; w = 0 ;the tub is empty.
1: After 20 minutes, the bathtub is empty.
B:P (4)= 10 `; At t = 4, w = 10 ; height of water in bath tub is 10
4: The height of the water is 10 inches after 4 minutes
C:P (10) = 4 ; At t = 10, w =4, height of water in bathtub = 4 inches
3: After 10 minutes, the height of the water is 4 inches.
.