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Korolek [52]
3 years ago
11

What is the axis of symmetry of the quadratic function y=2(x+3)^2+5

Mathematics
1 answer:
Pavel [41]3 years ago
3 0

Answer:

x=-3

Step-by-step explanation:

The quadratic function y=2(x+3)^2+5 determines the parabola which has the vertex at point (-3,5). The axis of symmetry passes through the vertex and is parallel to the y-axis. Hence, its equation is x=-3 (see attached diagram).

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What are the coordinates of the point that is one half the distance between A(-1, -2) and B(6, 12)?
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The coordinates of the point that is one-half the distance between A(-1,-2) and B(6,12) is (2.5,5)

What is the midpoint?

The mid-point lies midway between the two ends. Its x value lies in the middle of the other two x values. Its y value lies in the middle of the other two y values.

Given, A(6,12) = (x_{1}, y_{1} )

           B(6,12) = (x_{2}, y_{2} )

Let M is a midpoint of AB, then

M(x,y)=(\frac{x_{1}+x_{2}  }{2} ,\frac{y_{1} +y_{2}}{2} )= (\frac{-1+6}{2} ,\frac{-2+12}{2} )=(2.5,5)

The midpoint of point AB is M(2.5,5)

Therefore, the coordinates of the point which is one-half the distance between A(-1,-2) and B(6,12) is M(2.5,5).

To learn more about the midpoint

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