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Lena [83]
3 years ago
15

What is the slope of the line that passes through the points (-9, -3) and (1, -3)?

Mathematics
1 answer:
anastassius [24]3 years ago
8 0

Answer:

The slope is 0.

Step-by-step explanation:

m= (y2-y1)/(x2-x1).

y2 is -3, y1 is -3.

x2 is 1 and x1 is -9.

m= -3 -(-3)/ 1- (-9)

m= 0/10

m=0

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Using Substitution solve: y=x+5<br> 4x+y=20
Vladimir [108]

Answer:

3

Step-by-step explanation:

So first, plugin y to your equation, it should look like this: 4x+x+5+20. Now, we can solve this. Next, we have two x's so we can combine them. The equation will now look like this: 5x+5=20. Now, we have an extra 5 laying around that we need to get rid of, so we can subtract that 5 to both sides of the equation and we get this: 5x-5=20-5 which ends up being 5x=15. Now, we just divide both ides by 5 and since 15 divided by 5 is 3, we get: x=3

4 0
3 years ago
Suppose that X represents for the number of fishes caught on a certain day at a Michigan lake, and there is no available informa
lisov135 [29]

Answer:

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Step-by-step explanation:

6 0
3 years ago
What is the absolute value of -3.75? (6.2B | 6.1B 6.1F)
ad-work [718]
Answer is 3.75
Absolute value is the numerical value
7 0
3 years ago
1) IF the area of the frame was 64inches², what would be 2 possible sets of dimensions that could be used to make a frame with t
neonofarm [45]
There are infinite possibilities for this answer, let's see how:
Assuming the frame is rectangular, and it has 64 square inches, then the multiplication of the height (H) and width (W) is 64.
So H*W=64, therefore H=64/W
Any pair of numbers that fits this equation will be a possible answer.
A few examples:
H=1; W=64
H=2; W=32
H=1,23456; W= 51,840338
H=4; W=16
H=8; W=8
etc.

So, for example, one set can be 8x8 inches
another set can be 4x16 inches

if the frame were to have 5 inches and 7 inches, since 1 inch correponds to 2.5ft, then we simply must multiply the values in inches per 2.5 to get the values in feet, then it would correspond to
5*2.5=12.5 ft  and   7*2.5=17.5 ft
7 0
4 years ago
A​ true/false test has 8080 questions. Suppose a passing grade is 5252 or more correct answers. Test the claim that a student kn
Makovka662 [10]
<h2>Answer with explanation:</h2>

Let p be the proportion of the correct answers.

As per given , we have

H_0: p=0.50

H_a: p>0.50 , since the alternative hypothesis is right tailed , so the test is a one -tailed test.

If the student gets 52 answers correct out of 80.

i.e. the proportion of correct answers : \dfrac{52}{80}=0.65

Test statistic : z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

z=\dfrac{0.65-0.50}{\sqrt{\dfrac{0.50(0.50)}{80}}}\approx2.68

P-value : P(z>2.68)=0.0037   [ by using p-value table for z (right-tailed)]

Since the p-value(0.0037) is less than the significance level (0.05), so we reject the null hypothesis.

Results : We have enough evidence to support the claim that a student knows more than half of the answers and is not just guessing.

8 0
3 years ago
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