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zmey [24]
3 years ago
6

A cereal company is creating new boxes for its product. In order to display the boxes, the stores they sell to require that the

boxes be 11.5 inches high and no longer than 8.4 inches. The printing department requires exactly 272.8 square inches of space in order to use the planned design that covers the box. If the company wishes to maximize the length of the box, then what should be the width of the box?
Mathematics
1 answer:
SashulF [63]3 years ago
3 0

If the problem says "space", that usually means that they are talking about volume. The maximum length the box can be is 8.4 inches. To find volume, you do length * width * height. You know the length and height, as well as the volume. You can replace the width with "x". Your equation should be:

11.5 * 8.4 * x = 272.8

Then you can just solve for x by dividing both sides by (11.5 * 8.4). The answer should be about 2.82 inches.

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Tim's bean sprout grew 3/ inches. Teegan's bean sprout grew 2 3/4 inches. How many more inches did Tim's bean sprout grow than T
ki77a [65]

Answer:

Tim's bean sprout grow by more than \frac{5}{8} \text{ inches}.

Step-by-step explanation:

We are given that Tim's bean sprout grew 3 3/8 inches. Teegan's bean sprout grew 2 3/4 inches.

We have to find how many more inches did Tim's bean sprout grow than Teegan's.

Firstly, converting both the mixed fractions in improper fraction get;

Tim's bean sprout grew = 3\frac{3}{8} = \frac{27}{8} \text{ inches}

Teegan's bean sprout grew = 2\frac{3}{4} = \frac{11}{4} \text{ inches}

Since the denominator of both the fractions is not the same, so we can't compare them both as which is larger or smaller.

Tim's bean sprout grew = \frac{27\times 1}{8\times 1} = \frac{27}{8} \text{ inches}

Teegan's bean sprout grew = \frac{11 \times 2}{4\times 2}=\frac{22}{8} \text{ inches}

Now, we can clearly see that Tim's bean sprout grew more than Teegan's bean sprout.

So, Tim's bean sprout grow by more than = \frac{27}{8}- \frac{22}{8} = \frac{5}{8} \text{ inches}

Hence, Tim's bean sprout grow by more than \frac{5}{8} \text{ inches}.

8 0
3 years ago
Can someone help with 1 11/15 divided by 1 4/9?
Ket [755]

Answer: The answer is 1 1/5

Step-by-step explanation: Hope that helps :)

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Answer:

ind the absolute value vertex. In this case, the vertex for y=−|x|−2 is (0,−2).

(0,−2)

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Interval Notation:

(−∞,∞)

Set-Builder Notation:  {x|x ∈ R}

For each x value, there is one y value. Select few x values from the domain. It would be more useful to select the values so that they are around the x value of the absolute value vertex.

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Step-by-step explanation:

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