Three important properties of the diagonals of a rhombus that we need for this problem are:
1. the diagonals of a rhombus bisect each other
2. the diagonals form two perpendicular lines
3. the diagonals bisect the angles of the rhombus
First, we can let O be the point where the two diagonals intersect (as shown in the attached image). Using the properties listed above, we can conclude that ∠AOB is equal to 90° and ∠BAO = 60/2 = 30°.
Since a triangle's interior angles have a sum of 180°, then we have ∠ABO = 180 - 90 - 30 = 60°. This shows that the ΔAOB is a 30-60-90 triangle.
For a 30-60-90 triangle, the ratio of the sides facing the corresponding anges is 1:√3:2. So, since we know that AB = 10, we can compute for the rest of the sides.



Similarly, we have



Now, to find the lengths of the diagonals,


So, the lengths of the diagonals are 10 and 10√3.
Answer: 10 and 10√3 units
Answer: FALSE
When you multiply an inequality by a negative number the inequality flips.
Answer:
x = 7
Step-by-step explanation:
Notice that in the triangle, the angle is either known or in terms of x. This means we can make an equation: 82 + (9x - 6) + (6x - 1) = 180. Now, add up tthe terms to get 15x + 75 = 180, or 15x = 105 or x = 7.
First, you do the distributive property on:
4(2n+3)
You would get
8n+12
Then add the original part of the equation in (4n)
4n+8n+12
Combine like terms
12n+12 is the answer