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worty [1.4K]
3 years ago
13

Find the area of a rectangle whose vertices are (2,1), (2,11), (9,1), and (9,11).

Mathematics
1 answer:
lys-0071 [83]3 years ago
5 0
The answer that I got when doing the calculations is A=70.
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Step-by-step explanation:

i just am to stupid to be honest

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select all correct answers choices , which one are they ? 1,2,3,4,5,6 , you can pick more than 1 , please help me
SpyIntel [72]
The first and third one make the most sense
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The radius of a semicircle is 2 feet. What is the semicircle's diameter?
fomenos

Answer:

11/7 feet

Step-by-step explanation:

Perimeter of a circle = pi

Semicircle would be 1/2 of pi

1/2 × 22/7 × 1

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4x(x + 3) +7x = what is the answer please
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3 years ago
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Ten members of a wedding party are lining up in a row for a photograph. How many ways are there to line up the ten people? How m
svp [43]

Answer:

(a) 10!

(b) 9!

(c) 2!9!

Step-by-step explanation:

(a)

Total number of members = 10

We need to line up the ten people.

Total number of ways to arrange n terms is n!. Similarly, total number of ways to line up the ten people is

\text{Total ways} =10!

Therefore the total number of ways to line up the ten people is 10!.

(b)

Let groom is immediate left of the bride it means both will sit together. So we need to arrange peoples for total 9 places (8 of others and 1 of bride and groom).

\text{Total ways} =9!1!1!=9!

Therefore the number of ways to line up the ten people if the groom must be to the immediate left of the bride in the photo is 9!.

(c)

Let groom is immediate left of the bride it means both will sit together. So we need to arrange peoples for total 9 places (8 of others and 1 of bride and groom).

Bride and groom can interchange there sits.

Total number of ways to arrange bride and groom = 2!

\text{Total ways} =9!2!

Therefore the number of ways to line up the ten people if the groom must be next to the bride (either on her left to right side) is 9!2!.

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3 years ago
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