Find the area of a rectangle whose vertices are (2,1), (2,11), (9,1), and (9,11).
1 answer:
You might be interested in
Answer:
a. Function 1
b. Function 3
c. Function 2, Function 3 and Function 4
Step-by-step explanation:
✔️Function 1:
y-intercept = -3 (the point where the line cuts across the y-axis)
Slope, using the two points (0, -3) and (1, 2):
Slope = 5
✔️Function 2:
y-intercept = -1 (the value of y when x = 0)
Slope, using the two points (0, -1) and (1, -4):
Slope = -3
✔️Function 3: y = 2x + 5
y-intercept (b) = 5
Slope (m) = 2
✔️Function 4:
y-intercept = 2
Slope = -1
Thus, the following conclusions can be made:
a. The function's graph that is steepest is the function whose absolute value of its slope is greater. Therefore Function 1 is the steepest with slope of 5
b. Function 3 has a y-intercept of 5, which is the farthest from 0.
c. Function 2, Function 3, and Function 4 all have y-intercept that is greater than -2.
-1, 5, and 2 are all greater than -2.