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Misha Larkins [42]
2 years ago
13

Gretchen earns extra money mowing lawns on the weekend. She mows 3 lawns per hour and earns $12.00 per lawn. How much does Gretc

hen earn for 4 hours of mowing lawns? Enter your answer in the box.
Mathematics
1 answer:
stepladder [879]2 years ago
4 0

Gretchen will earn $48 from mowing in 4 hours

Data

  • Amount earned on each lawn = $12
  • Number of hours mowing = 4 hours

<h3>What is Rate</h3>

This is the measure of one unit against another unit. An example of this is speed which is the rate of distance covered to time.

In this case, she mows 1 lawn in each hour and earns $12 on each.

To calculate for 4 hours

4*12=$48

She earns $48 from mowing 4 lawns

learn more on rates here;

brainly.com/question/8728504

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Write the point-slope form of an equation of the line through the points (-2, -3) and (-7, 4).
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7x+5y +29= 0
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2 years ago
Find the value of x. Round to the nearest tenth.
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What is the growth factor associated with the following growth rate: 30% decrease
fenix001 [56]

Given:

Growth rate = 30% decrease

To find:

The growth factor associated with the given growth rate.

Solution:

The general exponential function is:

y=a(1+r)^x

y=a(b)^x

Where, a is the initial value, r is the growth rate in decimal and b=1+r is the growth factor.

It is given that the growth rate is 30% decrease. So,

r=-30\%

r=-\dfrac{30}{100}

r=-0.3

Now,

b=1+r

b=1+(-0.3)

b=1-0.3

b=0.7

Therefore, the growth factor is 0.7.

5 0
3 years ago
The ratio of working-age population to the elderly in the United States (including projections after 2000) is given by the funct
Dovator [93]

Answer:

a) Sketch the graph of the function f. (it is in the attached file)

b) What was the ratio at the beginning of 2006? At the beginning of 2014?

For 2006 the ratio is 3.92

For 2014 the ratio is 3.5

c) Over what years is the ratio constant?

[1995, 2000]

d) Over what years is the decline of the ratio greatest?

[2010, 2030]

Step-by-step explanation:

b) We first need to know in between which function 2006 falls into, so if we start in t=0=1995, then 2006-1995=11, t=11

t=11 fall into:

f(x)=-0.03t+4.25

f(11)=-0.03(11)+4.25=3.92

For 2006 the ratio is 3.92

2014:

Same process that 2006, t=0=1995, then 2014-1995=19, t=19

t=19fall into:

f(x)=-0.075t+4.925

f(19)=-0.075(11)+4.925=3.5

For 2014 the ratio is 3.5

c) The ratio is only constant in the first section of the graph 0≤t<5, since 4.1 is constant. Following the same process for the years in star (b) we have t=0, 1995+0=1995, t=5, 1995+5=2000.

The ratio will be constant between [1995, 2000]

d) For the greatest decline we need to compare slopes. From the line equation we have:

y(x)=mx+b where m is the slope and b is the point the line intersects with the y axis. Here we have:

f(x)=-0.03t+4.25  for 5≤t<15

f(x)=-0.075t+4.925  for 15≤t≤35

So:

m=-0.03 for 5≤t<15

m=-0.075 for 15≤t≤35

If we are measuring the steepness of the decline, we have to compare:

|-0.03| and |-0.075| or 0.03 and 0.075, easily finding that 0.075>0.03

And doing the sames process for the years in question (c):

t=15, 1995+15=2010, and t=35, 1995+35=2030

This means that the biggest decline is between the years:

[2010, 2030]

3 0
3 years ago
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