Answer:
s = 22.5 m
Step-by-step explanation:
the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.
v (t) = 25 - 5 t
at t = 0 , v = 20 m/s
Let the distance is s.

Let at t = t, the v = 20
So,
20 = 25 - 5 t
t = 1 s
So, s = 25 x 1 - 2.5 x 1 = 22.5 m
Answer:
= 4/15
Step-by-step explanation:
=4 . 2/5 /6
= 4/15
Answer:
3.3
Step-by-step explanation:
logging in and answering
-3
step by step
add 2 to -11 and divide-9 by 3
Answer:
Step-by-step explanation:
2/5x + 6=3/4x-8