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VLD [36.1K]
3 years ago
5

(r-3)(r+6) multiply need the answer now

Mathematics
1 answer:
Hitman42 [59]3 years ago
5 0

Answer:

r^2+3r-18

Step-by-step explanation:

       r     6

r     r^2   6r

-3    -3r   -18

r^2 + 6r - 3r - 18

r^2+3r-18

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The vertices of quadrilateral MNPQ are M(−3,−2),N(−1,4),P(2,4), and Q(4,−2). Translate quadrilateral MNPQ using the vector ⟨3,−4
muminat

Answer:

see explanation

Step-by-step explanation:

A translation using the vector < 3, - 4 > , means

Add 3 to the x- coordinate and subtract 4 from the y- coordinate, so

M (- 3, - 2 ) → M' (- 3 + 3, - 2 - 4 ) → M' (0, - 6 )

N (- 1, 4 ) → N' (- 1 + 3, 4 - 4 ) → N' (2, 0 )

P (2, 4 ) → P' (2 + 3, 4 - 4 ) → P' (5, 0 )

Q (4, - 2 ) → Q' (4 + 3, - 2 - 4 ) → (7, - 6 )

4 0
3 years ago
In a random sample of students who took the SAT test, 427 had paid for coaching courses and the remaining 2733 had not. Calculat
Dvinal [7]

Answer:

The 95% confidence interval for the proportion of students who get coaching on the SAT is (0.1232, 0.147).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

427 had paid for coaching courses and the remaining 2733 had not.

This means that n = 427 + 2733 = 3160, \pi = \frac{427}{3160} = 0.1351

95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1351 - 1.96\sqrt{\frac{0.1351*0.8649}{3160}} = 0.1232

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1351 + 1.96\sqrt{\frac{0.1351*0.8649}{3160}} = 0.147

The 95% confidence interval for the proportion of students who get coaching on the SAT is (0.1232, 0.147).

8 0
3 years ago
Someone help me please:)
IRISSAK [1]
Im not that good with these types of problems but i think it is b if my math is correct.
6 0
3 years ago
For the arthritic sequence 5,9,13,17,21,... how many terms would you need to get to 129
Vlad1618 [11]

9514 1404 393

Answer:

  32

Step-by-step explanation:

The first term is 5 and the common difference is 9-5=4, so the n-th term is ...

  an = a1 +d(n -1)

  an = 5 +4(n -1) = 4n +1

Then the term number for the term 129 is ...

  129 = 4n +1 . . . . . put the given value in the formula

  128 = 4n  . . . . . . . subtract 1

  32 = n . . . . . . . . . .divide by 4

The 32nd term is 129.

8 0
3 years ago
A culture of bacteria doubles every hour. If there are 500 bacteria at the beginning, how many bacteria will there be after 24 h
Mama L [17]
<span>8388608000. you will have to keep multiplying 2 24 times.</span>
3 0
3 years ago
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